Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 7)
7.
Three lights are connected in parallel across a 120 volt source. If one light burns out,
Discussion:
15 comments Page 1 of 2.
Anand said:
1 decade ago
In series circuit voltage remains same on each circuit, if parallel voltage is different.
Muthumayil said:
1 decade ago
Anand your answer is wrong. In series ckt current is same, if parallel voltage will be the same.
Ramu said:
1 decade ago
The remaining two lights glow same as earlier. Because in parallel circuit voltage is same. Since each bulb is receiving some currents separately, These will glow independently. Suppose third branch line is cutting, third bulb will not glow. The remaining two will glow continuously because these two bulb is receiving separate current from source.
Sushil said:
1 decade ago
Theoretically it is correct but practically it is wrong. Practically answer should be (B).
Yathi said:
1 decade ago
The current flowing to the third bulb will be diverted to the other two bulbs, so the other two bulbs will glow brighter.
VAGEESH said:
1 decade ago
The voltage is same in all the 3 branches in case of parallel circuit. So other two bulbs will be continue to glow with same brightness as before.
PRAKASH said:
1 decade ago
Answer can be (C) also because when the 3rd bulb will blow out, that means NO resistance, then it would be a short-circuit path for the current and so, all the current will flow through the short-circuited branch and other two bulbs would not receive any current at all.
NAVEEN said:
1 decade ago
@Prakash you are wrong, if 3rd bulb blows out it will become open circuit.
Siva said:
10 years ago
Absolutely, @Prakash is wrong, if any bulb is blow out, that means is will be opened circuit.
Shashidhra said:
9 years ago
Option D, is correct.
Because the resistance of remaining two bulbs remain same and voltage of bulb remains same. So current also remains same. The power consumed by the bulb remains same.
Because the resistance of remaining two bulbs remain same and voltage of bulb remains same. So current also remains same. The power consumed by the bulb remains same.
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