Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 25)
25.
In a five-branch parallel circuit, there are 12 mA of current in each branch. If one of the branches opens, the current in each of the other four branches is
Discussion:
22 comments Page 1 of 3.
Abhijith said:
7 years ago
There are 5 branches, current in each branch is 12, so total current = i1 + i2 + i3 + i4 + i5 = 60.
Then one branch is an open circuit, that means there is no current in that branch, take i2 = 0,
(if i2 brach taken as opn) so total current will decrease, i1 + 0 + i3 + i4 + i5 = 48 (12 * 4).
So, current in each branch is 12 (48÷4), there are equal resistance in each branch.
Then one branch is an open circuit, that means there is no current in that branch, take i2 = 0,
(if i2 brach taken as opn) so total current will decrease, i1 + 0 + i3 + i4 + i5 = 48 (12 * 4).
So, current in each branch is 12 (48÷4), there are equal resistance in each branch.
(1)
Senthamizh said:
7 years ago
The question is about other branch current. Not total current. So it will remain unaffected.
(1)
Waryam said:
8 years ago
Current through 5 branches = 60mA.
If one branch is open then resistance = 12+12+12+12+R= 60.
i.e 48+R= 60.
& R=60-48=12.
If one branch is open then resistance = 12+12+12+12+R= 60.
i.e 48+R= 60.
& R=60-48=12.
(1)
Sushil ram said:
8 years ago
Well said @Prashant Jayant.
Aizaz haider said:
5 years ago
@Piyush Kanani.
Thank you for explaining the right answer.
Thank you for explaining the right answer.
Bhaskar said:
5 years ago
Yes, I agree with you@Ashwath.
Piyush Kanani said:
6 years ago
Imagine system voltage = Y.
The resistance of each branch = X.
During the 5 branches system total resistance = X/5.
So, V=IR= 60*(X/5) = 12X.
So, Y=12X.
NOW, during 4 branches system total resistance = X/4.
So, V = IR= I*(X/4).
I = V/(X/4).
= 12X/(X/4).
= 48.
Which divided into 4 parallel branches so par branch 12.
The resistance of each branch = X.
During the 5 branches system total resistance = X/5.
So, V=IR= 60*(X/5) = 12X.
So, Y=12X.
NOW, during 4 branches system total resistance = X/4.
So, V = IR= I*(X/4).
I = V/(X/4).
= 12X/(X/4).
= 48.
Which divided into 4 parallel branches so par branch 12.
Tanim Hossain said:
7 years ago
@All.'
The Answer B is correct, because the question is (current in each of the other four branches).
The Answer B is correct, because the question is (current in each of the other four branches).
Senthamizh said:
7 years ago
Yes, correct @Amit.
Bibek said:
7 years ago
It should be 15. Because no current flows in open circuit.
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