Electrical Engineering - Parallel Circuits - Discussion
Discussion Forum : Parallel Circuits - General Questions (Q.No. 11)
11.
A 470
resistor, a 220
resistor, and a 100
resistor are all in parallel. The total resistance is approximately



Answer: Option
Explanation:
1/R = (1/470 + 1/220 + 1/100)
R = 59.98 ohm
R = 59.98 ohm
Discussion:
11 comments Page 1 of 2.
Vinny said:
7 years ago
Assume 470,220 and100 as r1 r2 r3 respectively. So,
1/rt=(1/r1)+(1/r2)+(1/r3),
=0.00212+0.00454+0.01=0.0166,
So, 1/0.0166= 60.1&ohms;.
1/rt=(1/r1)+(1/r2)+(1/r3),
=0.00212+0.00454+0.01=0.0166,
So, 1/0.0166= 60.1&ohms;.
(2)
Somashekar said:
1 decade ago
How the R is 59.98?
The answer wrong according to the formula of parallel resistance.
The answer wrong according to the formula of parallel resistance.
Deepa said:
7 years ago
Can you give clear explanation about parallel connection with the correct formula?
Bien said:
4 years ago
Rt= (470^-1 + 220^-1 + 100^-1)^-1.
round up = 60.
round up = 60.
Indr said:
8 years ago
How to solve this equation without calsi ?
Bharat gohil said:
10 years ago
Formula and answer both are correct.
Bharat Gohil said:
10 years ago
Answer is right as per formula.
Sucharitha said:
8 years ago
Formula r1*r2*r3/r1+r1+r2+r3.
Abdul Kareem said:
10 years ago
How 59.98 is correct answer?
Waryam said:
8 years ago
Please explain @Sucharitha.
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