Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 22)
22.
Approximately how much current flows through a 3.3 M resistor across a 30 V source?
9 A
90 A
900 A
9000 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
9 comments Page 1 of 1.

Mohibullah Shah said:   3 years ago
As we have to find current so I = V/R.

So I = 30/3.3000000.

I = 0.0000090909,
I= (0.0000090909 * 10^+6 ) * (10^-6).
I= 9.09 uA.
(1)

Pan chod said:   4 years ago
Can someone simplify it? please.

Aqil Hussain said:   9 years ago
V = IR.
v = 30v.
r = 3.3 M ohms.
I = ?

Solve,

I = V/R
I = 30/3.3 M ohms
I= 9 Micro Amperes.

Jmb said:   10 years ago
Clarification;

1 Ohm = 10^6 Megohms.

1 Ohm = 10^-6 micro ohms.

*Note: This is like proportion for converting from Mega to micro.

*10^6 Mega ohms = 10^-6 micro ohms.

* So multiply both side with 1/6 then the see the result.

Always remember this formula: P = IV = I^2*R = V^2/R.

Then I = V/R.

I = 30/3.3 micro ohms.

I = 9.090909 micro ohms.

So answer is A.

Nansu said:   10 years ago
Please explain clearly.

Suraj rawat said:   1 decade ago
I don't know how can solve this question?

Deep said:   1 decade ago
As we have to find current so I = V/R.

So I = 30/3.3000000.

I = 9uA.

MURUGAPERUMAL said:   1 decade ago
I=V/R,

SO, I=30/3. 3000000.

I=9. 09*10^6.

I=9 µA.

Arun Sankar P said:   1 decade ago
1Kohm=10^3 ohms
1Mohm=10^6 ohms

1 M ohm=1000 ohms
so,formula for I=V/R
I=30/3.3M ohms
I=9000M ohms
I=9milli ohms

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