Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 24)
24.
What is the approximate filament resistance of a light bulb if it operates from a 110 V source and 0.6 A of current is flowing?
183 
18.3
66
6.6
Discussion:
4 comments Page 1 of 1.
Mazarpasha kj said:
9 years ago
R = V/I.
110/0.6 = 183.33 ohm.
110/0.6 = 183.33 ohm.
(1)
Sanjith said:
9 years ago
=> V/I = 110/.6.
= 183.
= 183.
(1)
Bhabani shankar behera said:
1 decade ago
183.3.
Because when we calculate.
V/i = 110/0.6 = 183.3333333.
Please calculate this.
Because when we calculate.
V/i = 110/0.6 = 183.3333333.
Please calculate this.
MURUGAPERUMAL said:
1 decade ago
R=V/I
R=110/.6
R=183 OHMS.
R=110/.6
R=183 OHMS.
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