Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 20)
20.
Twelve volts are applied across a resistor. A current of 3 mA is measured. What is the value of the resistor?
4 
400
4 k
4.4
Discussion:
6 comments Page 1 of 1.
AKASH said:
3 years ago
v = 12,
I = 3 * 10^-3 A,
R = v/I, = 12/3X10^-3=4X10^3 ohms=4K ohms.
I = 3 * 10^-3 A,
R = v/I, = 12/3X10^-3=4X10^3 ohms=4K ohms.
Manohar said:
6 years ago
Please read the question properly @manjunath.
Manjunath said:
7 years ago
How you can take 12v? explain.
Bhaveshkumar B Detroja said:
10 years ago
SIMPLE TRICK:
R : V/I.
R : 12/3*10^-3.
R : 12*10^3/3.
R : 12000/3.
R : 4000 OHM.
R : 4 KILO OHM.
R : V/I.
R : 12/3*10^-3.
R : 12*10^3/3.
R : 12000/3.
R : 4000 OHM.
R : 4 KILO OHM.
Abhishek Sathua said:
1 decade ago
I'm glad to do the exercises, I think it is the best site for students.
(1)
Anand said:
1 decade ago
v=12,
I=3X10^-3 A,
R=v/I,=12/3X10^-3=4X10^3 ohms=4K ohms
I=3X10^-3 A,
R=v/I,=12/3X10^-3=4X10^3 ohms=4K ohms
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