Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 25)
25.
What is the approximate resistance of a rheostat if the voltage source is 18 V and the current is 220 mA?
8.2 k
820
8.2
82
Discussion:
8 comments Page 1 of 1.
Yash said:
4 years ago
Thanks all for solving the answer.
Lekan said:
6 years ago
v=IR,.
I=V/R.
18Ω.
I=V/R.
18Ω.
Ravi said:
8 years ago
I = 220 * 10^-3 = 220/1000,
V = 18,
R = V/I = 18/(220/1000),
R = (18 * 1000)/220,
R = 900/11,
R = 81.9.
Answer:- R~82 OHM.
V = 18,
R = V/I = 18/(220/1000),
R = (18 * 1000)/220,
R = 900/11,
R = 81.9.
Answer:- R~82 OHM.
Gopi Reddy said:
1 decade ago
R = V/I.
R = 18/220.
R = 0.08181*10^3.
R = 81.81.
Approximately value R=82 ohms.
R = 18/220.
R = 0.08181*10^3.
R = 81.81.
Approximately value R=82 ohms.
Sankaragomathi said:
1 decade ago
I=V/R
R=18/(220*10^-3)
R=0.0818*10^3
R=81.8
SO APPROM ITS 82OHM
R=18/(220*10^-3)
R=0.0818*10^3
R=81.8
SO APPROM ITS 82OHM
Anand said:
1 decade ago
v=18,I=220X10^-3 A,
R=V/I,
R=18/220X10^-3 = 0.0818X10^3=81.8=82 ohm(approx)
R=V/I,
R=18/220X10^-3 = 0.0818X10^3=81.8=82 ohm(approx)
Sibananda chakra said:
1 decade ago
Thank you.
Ravinder said:
1 decade ago
r=v/i,
r=18/220/1000,
r=18*1000/220
=18000/220
=1800/22
=81.82
=82 approximately
r=18/220/1000,
r=18*1000/220
=18000/220
=1800/22
=81.82
=82 approximately
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