Electrical Engineering - Ohm's Law - Discussion

Discussion :: Ohm's Law - General Questions (Q.No.15)

15. 

If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is

[A]. 220 k
[B]. 22 k
[C]. 2.2 k
[D]. 220

Answer: Option C

Explanation:

No answer description available for this question.

Raghu said: (Mar 3, 2011)  
V=RI
24/0.0109=2201 means 2.2KV

Varatharajan said: (Jan 7, 2012)  
Hi raghu, are you understand for the sum. The sum is required to resistance value.

So the answer is R=V/I

R=24/10.9*10^-3
R=2.2*10^-3
R=2.2KOhm

Sowjanya said: (Mar 12, 2014)  
R= V/I.
R= 24/10.9*10^-3.
R= 2.2 kohm.

Ali Shan said: (Dec 28, 2014)  
I am not satisfied to all explanation please tell me about your question.

Arun said: (Mar 12, 2016)  
R = V/I.

Ramalingam said: (Jul 29, 2016)  
24 / 10.90000 = 2.20183481.

Ashok said: (Jun 4, 2017)  
Thank you everyone for the given explanation.

Gowri said: (Jul 15, 2019)  
v = IR.
R = V/I.
R = 24/10.9*10^-3 =2.2*10^3.
R = 2.2 Kiloohm.

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