Electrical Engineering - Ohm's Law - Discussion
Discussion Forum : Ohm's Law - General Questions (Q.No. 15)
15.
If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is
Discussion:
11 comments Page 1 of 2.
SASMITA MAHALIK said:
2 months ago
V = RI.
20/0.0109 = 2201 V.
So, mean 1000V = 1KV,
2201/1000=2.2 KV,
And the right answer is 2.2 KV.
20/0.0109 = 2201 V.
So, mean 1000V = 1KV,
2201/1000=2.2 KV,
And the right answer is 2.2 KV.
Aakarsh Chandra said:
3 years ago
Given = voltage = 24v
Current = 10.9 mA
Resistance = ?
Let's find it,
V = IR.
R = V/I.
R = 24/10.9*10^-3,
R = 24*1000/10.9,
R = 240000/109,
R = 2201.83 (ohm),
=> 2201.83/1000 = 2.20 k ( ohm).
Current = 10.9 mA
Resistance = ?
Let's find it,
V = IR.
R = V/I.
R = 24/10.9*10^-3,
R = 24*1000/10.9,
R = 240000/109,
R = 2201.83 (ohm),
=> 2201.83/1000 = 2.20 k ( ohm).
Koushik said:
5 years ago
By using Ohms Law.
R=V/I = 24÷10.9 =2.2kilo Ohm.
R=V/I = 24÷10.9 =2.2kilo Ohm.
Gowri said:
6 years ago
v = IR.
R = V/I.
R = 24/10.9*10^-3 =2.2*10^3.
R = 2.2 Kiloohm.
R = V/I.
R = 24/10.9*10^-3 =2.2*10^3.
R = 2.2 Kiloohm.
Ashok said:
8 years ago
Thank you everyone for the given explanation.
Ramalingam said:
9 years ago
24 / 10.90000 = 2.20183481.
Arun said:
10 years ago
R = V/I.
ALI SHAN said:
1 decade ago
I am not satisfied to all explanation please tell me about your question.
Sowjanya said:
1 decade ago
R= V/I.
R= 24/10.9*10^-3.
R= 2.2 kohm.
R= 24/10.9*10^-3.
R= 2.2 kohm.
Varatharajan said:
1 decade ago
Hi raghu, are you understand for the sum. The sum is required to resistance value.
So the answer is R=V/I
R=24/10.9*10^-3
R=2.2*10^-3
R=2.2KOhm
So the answer is R=V/I
R=24/10.9*10^-3
R=2.2*10^-3
R=2.2KOhm
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