Electrical Engineering - Ohm's Law - Discussion

Discussion Forum : Ohm's Law - General Questions (Q.No. 15)
15.
If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is
220 k
22 k
2.2 k
220
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
11 comments Page 1 of 2.

SASMITA MAHALIK said:   2 months ago
V = RI.
20/0.0109 = 2201 V.
So, mean 1000V = 1KV,
2201/1000=2.2 KV,
And the right answer is 2.2 KV.

Aakarsh Chandra said:   3 years ago
Given = voltage = 24v
Current = 10.9 mA
Resistance = ?

Let's find it,

V = IR.
R = V/I.
R = 24/10.9*10^-3,
R = 24*1000/10.9,
R = 240000/109,
R = 2201.83 (ohm),

=> 2201.83/1000 = 2.20 k ( ohm).

Koushik said:   5 years ago
By using Ohms Law.

R=V/I = 24÷10.9 =2.2kilo Ohm.

Gowri said:   6 years ago
v = IR.
R = V/I.
R = 24/10.9*10^-3 =2.2*10^3.
R = 2.2 Kiloohm.

Ashok said:   8 years ago
Thank you everyone for the given explanation.

Ramalingam said:   9 years ago
24 / 10.90000 = 2.20183481.

Arun said:   10 years ago
R = V/I.

ALI SHAN said:   1 decade ago
I am not satisfied to all explanation please tell me about your question.

Sowjanya said:   1 decade ago
R= V/I.
R= 24/10.9*10^-3.
R= 2.2 kohm.

Varatharajan said:   1 decade ago
Hi raghu, are you understand for the sum. The sum is required to resistance value.

So the answer is R=V/I

R=24/10.9*10^-3
R=2.2*10^-3
R=2.2KOhm


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