# Electrical Engineering - Ohm's Law - Discussion

### Discussion :: Ohm's Law - General Questions (Q.No.15)

15.

If 24 V are applied across a resistor and there are 10.9 mA of current, the resistance is

 [A]. 220 k [B]. 22 k [C]. 2.2 k [D]. 220 Explanation:

No answer description available for this question.

 Raghu said: (Mar 3, 2011) V=RI 24/0.0109=2201 means 2.2KV

 Varatharajan said: (Jan 7, 2012) Hi raghu, are you understand for the sum. The sum is required to resistance value. So the answer is R=V/I R=24/10.9*10^-3 R=2.2*10^-3 R=2.2KOhm

 Sowjanya said: (Mar 12, 2014) R= V/I. R= 24/10.9*10^-3. R= 2.2 kohm.

 Ali Shan said: (Dec 28, 2014) I am not satisfied to all explanation please tell me about your question.

 Arun said: (Mar 12, 2016) R = V/I.

 Ramalingam said: (Jul 29, 2016) 24 / 10.90000 = 2.20183481.

 Ashok said: (Jun 4, 2017) Thank you everyone for the given explanation.

 Gowri said: (Jul 15, 2019) v = IR. R = V/I. R = 24/10.9*10^-3 =2.2*10^3. R = 2.2 Kiloohm.

 Koushik said: (Jul 21, 2020) By using Ohms Law. R=V/I = 24÷10.9 =2.2kilo Ohm.