### Discussion :: Magnetism and Electromagnetism - General Questions (Q.No.2)

Dan said: (Apr 27, 2011) | |

How do I figure this answer out? is there a specific formula? |

Rohit said: (Jun 9, 2011) | |

Induced voltage=no of turns*rate of change of magnetic field. |

Bk Samal said: (Sep 2, 2011) | |

e=speed*rate of change of flux |

Shobhan Kumar Dash said: (Aug 27, 2012) | |

V= N* {d(phi)/dt} Here N = No. of turns of coil = 250 turns d(phi)/dt = Rate of change of flux = 8 Wb/Sec. Hence V= 250 * 8 = 2000 Volt (Ans) |

Faheem said: (Jan 29, 2014) | |

Induced voltage= - no of turns x rate of change of mag.flux. |

Venkatesh said: (Jun 22, 2014) | |

Number of turns multiplied by rate of change of flux linkages gives the induced voltage in the machine. |

Azaria said: (May 17, 2015) | |

250*8=2000 v. |

Amita said: (Apr 12, 2016) | |

Induced voltage is a multiplication of a number of turns and rate of change of flux. |

Rathod Prem said: (Aug 22, 2016) | |

Let us consider; Here V = N * {d(φ) /dt}. N = No of turns of coil = 250 turns. D(φ) /dt = Rate of change of flux = 8wb/sec. Hence V = 250 * 8 = 2000. |

Mahadev Nagargoje said: (Sep 9, 2016) | |

The induced voltage is a multiplication of a number of turns and rate of change of flux. |

Mukesh Kumar Pandey said: (Jan 13, 2017) | |

Induced voltage is equal than multiple for the rate of change of flux into number of turns I.e v = 250 * 8 = 2000 volt. |

Dodo said: (Nov 7, 2017) | |

The induced voltage is a multiplication of a number of turns and rate of change of flux. Hence, V = Ndphi/dt, V = 250*8. V = 2000V. |

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