# Electrical Engineering - Magnetism and Electromagnetism - Discussion

### Discussion :: Magnetism and Electromagnetism - General Questions (Q.No.2)

2.

The induced voltage across a coil with 250 turns that is located in a magnetic field that is changing at a rate of 8 Wb/s is

 [A]. 1,000 V [B]. 2,000 V [C]. 31.25 V [D]. 3,125 V

Explanation:

No answer description available for this question.

 Dan said: (Apr 27, 2011) How do I figure this answer out? is there a specific formula?

 Rohit said: (Jun 9, 2011) Induced voltage=no of turns*rate of change of magnetic field.

 Bk Samal said: (Sep 2, 2011) e=speed*rate of change of flux

 Shobhan Kumar Dash said: (Aug 27, 2012) V= N* {d(phi)/dt} Here N = No. of turns of coil = 250 turns d(phi)/dt = Rate of change of flux = 8 Wb/Sec. Hence V= 250 * 8 = 2000 Volt (Ans)

 Faheem said: (Jan 29, 2014) Induced voltage= - no of turns x rate of change of mag.flux.

 Venkatesh said: (Jun 22, 2014) Number of turns multiplied by rate of change of flux linkages gives the induced voltage in the machine.

 Azaria said: (May 17, 2015) 250*8=2000 v.

 Amita said: (Apr 12, 2016) Induced voltage is a multiplication of a number of turns and rate of change of flux.

 Rathod Prem said: (Aug 22, 2016) Let us consider; Here V = N * {d(φ) /dt}. N = No of turns of coil = 250 turns. D(φ) /dt = Rate of change of flux = 8wb/sec. Hence V = 250 * 8 = 2000.

 Mahadev Nagargoje said: (Sep 9, 2016) The induced voltage is a multiplication of a number of turns and rate of change of flux.

 Mukesh Kumar Pandey said: (Jan 13, 2017) Induced voltage is equal than multiple for the rate of change of flux into number of turns I.e v = 250 * 8 = 2000 volt.

 Dodo said: (Nov 7, 2017) The induced voltage is a multiplication of a number of turns and rate of change of flux. Hence, V = Ndphi/dt, V = 250*8. V = 2000V.