Electrical Engineering - Magnetism and Electromagnetism - Discussion

Discussion :: Magnetism and Electromagnetism - General Questions (Q.No.2)

2. 

The induced voltage across a coil with 250 turns that is located in a magnetic field that is changing at a rate of 8 Wb/s is

[A]. 1,000 V
[B]. 2,000 V
[C]. 31.25 V
[D]. 3,125 V

Answer: Option B

Explanation:

No answer description available for this question.

Dan said: (Apr 27, 2011)  
How do I figure this answer out? is there a specific formula?

Rohit said: (Jun 9, 2011)  
Induced voltage=no of turns*rate of change of magnetic field.

Bk Samal said: (Sep 2, 2011)  
e=speed*rate of change of flux

Shobhan Kumar Dash said: (Aug 27, 2012)  
V= N* {d(phi)/dt}

Here N = No. of turns of coil = 250 turns
d(phi)/dt = Rate of change of flux = 8 Wb/Sec.

Hence V= 250 * 8 = 2000 Volt (Ans)

Faheem said: (Jan 29, 2014)  
Induced voltage= - no of turns x rate of change of mag.flux.

Venkatesh said: (Jun 22, 2014)  
Number of turns multiplied by rate of change of flux linkages gives the induced voltage in the machine.

Azaria said: (May 17, 2015)  
250*8=2000 v.

Amita said: (Apr 12, 2016)  
Induced voltage is a multiplication of a number of turns and rate of change of flux.

Rathod Prem said: (Aug 22, 2016)  
Let us consider;

Here V = N * {d(φ) /dt}.
N = No of turns of coil = 250 turns.

D(φ) /dt = Rate of change of flux = 8wb/sec.

Hence V = 250 * 8 = 2000.

Mahadev Nagargoje said: (Sep 9, 2016)  
The induced voltage is a multiplication of a number of turns and rate of change of flux.

Mukesh Kumar Pandey said: (Jan 13, 2017)  
Induced voltage is equal than multiple for the rate of change of flux into number of turns I.e v = 250 * 8 = 2000 volt.

Dodo said: (Nov 7, 2017)  
The induced voltage is a multiplication of a number of turns and rate of change of flux.

Hence,

V = Ndphi/dt,

V = 250*8.
V = 2000V.

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