Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 2)
2.
The induced voltage across a coil with 250 turns that is located in a magnetic field that is changing at a rate of 8 Wb/s is
Discussion:
12 comments Page 1 of 2.
Dodo said:
7 years ago
The induced voltage is a multiplication of a number of turns and rate of change of flux.
Hence,
V = Ndphi/dt,
V = 250*8.
V = 2000V.
Hence,
V = Ndphi/dt,
V = 250*8.
V = 2000V.
(1)
Mukesh kumar pandey said:
8 years ago
Induced voltage is equal than multiple for the rate of change of flux into number of turns I.e v = 250 * 8 = 2000 volt.
(1)
Mahadev nagargoje said:
9 years ago
The induced voltage is a multiplication of a number of turns and rate of change of flux.
Rathod prem said:
9 years ago
Let us consider;
Here V = N * {d(φ) /dt}.
N = No of turns of coil = 250 turns.
D(φ) /dt = Rate of change of flux = 8wb/sec.
Hence V = 250 * 8 = 2000.
Here V = N * {d(φ) /dt}.
N = No of turns of coil = 250 turns.
D(φ) /dt = Rate of change of flux = 8wb/sec.
Hence V = 250 * 8 = 2000.
(5)
Amita said:
9 years ago
Induced voltage is a multiplication of a number of turns and rate of change of flux.
Azaria said:
10 years ago
250*8=2000 v.
Venkatesh said:
1 decade ago
Number of turns multiplied by rate of change of flux linkages gives the induced voltage in the machine.
Faheem said:
1 decade ago
Induced voltage= - no of turns x rate of change of mag.flux.
Shobhan Kumar Dash said:
1 decade ago
V= N* {d(phi)/dt}
Here N = No. of turns of coil = 250 turns
d(phi)/dt = Rate of change of flux = 8 Wb/Sec.
Hence V= 250 * 8 = 2000 Volt (Ans)
Here N = No. of turns of coil = 250 turns
d(phi)/dt = Rate of change of flux = 8 Wb/Sec.
Hence V= 250 * 8 = 2000 Volt (Ans)
Bk samal said:
1 decade ago
e=speed*rate of change of flux
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