Electrical Engineering - Magnetism and Electromagnetism - Discussion

Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 24)
24.
What is the reluctance of the circuit in problem 9 if the flux is 275 Wb?
0.0066 At/Wb
0.066 At/Wb
8,727 At/Wb
872 At/Wb
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
17 comments Page 1 of 2.

Mak said:   9 years ago
MMF value is in ampere-turns, this is analogous to the EMF which is in volts. MMF is in magnetic while EMF is an electric.

Gopalan said:   10 years ago
Question not clear ?

AT is not given?

Stuti kushwaha said:   10 years ago
Please solve anyone.

Mahesh said:   1 decade ago
Someone please clarify how 8,727 At/Wb answer will come?

Fan said:   1 decade ago
Circuit in problem 9? Really?

Prajith said:   1 decade ago
Reluctance = l/m0mrA.
l ==> length of the magnetic circuit.
m0 ==> permeability.
mr ==> relative permeability.
A==> area of cross section.

But how to solve this question?

Alice said:   1 decade ago
We need current and number of turns or mmf or length to find reluctance.

Deepak kumar senapati said:   1 decade ago
How will we derive the formula ?

Sudhakar said:   1 decade ago
Reluctance = L/(mu)A = inductance/((absolute permeability*relative permeability)*Area).

Naveen said:   1 decade ago
reluctance=l/(mA)
l-magnetic circuit length not the inductance
m-permeability
A-cross sectional area
flux and cross sectional area given for the problem we need l to find the reluctance..


Post your comments here:

Your comments will be displayed after verification.