Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 8)
8.
What is the flux density when the flux is 5.5 
Wb and the cross-sectional area is 6 × 10–3 m2?
Wb and the cross-sectional area is 6 × 10–3 m2?91.7 T
T917 T
T91 T
9.7 T
Discussion:
8 comments Page 1 of 1.
Tushar said:
7 years ago
Yes, it is 917 Micro T.
Naresh said:
8 years ago
917microT.
(1)
Manju said:
9 years ago
The answer should be in pico not in micro that is 917 pT.
Ashwini kumar said:
9 years ago
Flux density = flux / cross - sectional area.
(1)
Raju kumar singh said:
1 decade ago
Lets solve it
We have given flux density=5.5*10^-6 wb
And cross sectional area= 6*10^-3 m^2
We take
B=Q/A
B=flux density in tesla(T)
Q=magnetic flux in weber(wb)
A=cross section area in square metre
B=5.5*10^-6/6*10^-3 =(5.5*10-3)/6 =0.9166666 *10^-3
If you round of then you will be get
B=917microT ANS
We have given flux density=5.5*10^-6 wb
And cross sectional area= 6*10^-3 m^2
We take
B=Q/A
B=flux density in tesla(T)
Q=magnetic flux in weber(wb)
A=cross section area in square metre
B=5.5*10^-6/6*10^-3 =(5.5*10-3)/6 =0.9166666 *10^-3
If you round of then you will be get
B=917microT ANS
(2)
Jasminah said:
1 decade ago
Actually Siba Padhi is wrong Nd chandraprakash is right
Siba padhi said:
1 decade ago
You are wrong chandraprakash.
Flux density =Q/A^2
Flux density =Q/A^2
(1)
Chandraprakash said:
1 decade ago
Farmula
B=Q/A
B=Flux density,Q=flux,A=cross sec. Area
B=Q/A
B=Flux density,Q=flux,A=cross sec. Area
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