Electrical Engineering - Magnetism and Electromagnetism - Discussion
Discussion Forum : Magnetism and Electromagnetism - General Questions (Q.No. 13)
13.
What is the flux density in a magnetic field in which the flux in 0.1 m2 is 600
Wb?

Discussion:
5 comments Page 1 of 1.
Raaj said:
3 years ago
Flux density (B) = flux/Area of cross section (A)
B = Weber/Meter Square = Tesla.
B = 600*10^-6/0.1,
= 6000*10^-6,
= 6*10^-3,
= 0.006.
Or
B = 6000*10^-6 Tesla.
B = Weber/Meter Square = Tesla.
B = 600*10^-6/0.1,
= 6000*10^-6,
= 6*10^-3,
= 0.006.
Or
B = 6000*10^-6 Tesla.
(1)
Sunitha said:
9 years ago
FLUX DENSITY = FLUX/AREA.
B = 600*10^-6 wb/ 0.1 m^2,
B = 6000 micro.wb/m^2,
Tesla = wb/m^2.
B = 6000 microTesla.
B = 600*10^-6 wb/ 0.1 m^2,
B = 6000 micro.wb/m^2,
Tesla = wb/m^2.
B = 6000 microTesla.
Praveeen kumar said:
1 decade ago
flux density is defined as the flux lines of force passing from north to south pole in a specific region called as area.
So B = flux per area.
Then B = 600/0.1.
is 6000 micr0 Tesla.
So B = flux per area.
Then B = 600/0.1.
is 6000 micr0 Tesla.
Silambu said:
1 decade ago
B = flux/area.
B = 600/0.1 = 6000MicroT.
B = 600/0.1 = 6000MicroT.
Chandraprakash said:
1 decade ago
Use this farmula
B=Q/A
B=Q/A
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