Electrical Engineering - Inductors - Discussion

Discussion :: Inductors - General Questions (Q.No.7)

7. 

Two 10 H inductors are in parallel and the parallel combination is in series with a third 10 H inductor. What is the approximate total reactance when a voltage with a frequency of 7 kHz is applied across the circuit terminals?

[A]. 219 k
[B]. 66 k
[C]. 660 k
[D]. 1.3 M

Answer: Option C

Explanation:

No answer description available for this question.

Raja said: (Aug 4, 2011)  
Can any one explain this why ?

Asha said: (Oct 3, 2011)  
L equivalent=15H
reactance=wL=2*PIE*F*L

Shruthi Mathew said: (Jun 18, 2012)  
1/L(equa) = 1/L1 + 1/L2.
L(equa) = 5H.
L(equa)+10H = 15H.

XL = wL
= 2*3.14*f*L
= 2*3.14*7*1000*15
= 659.4*1000
= 660kohms.

Naresh said: (Jun 23, 2012)  
XL = wL.

= 2*3.14*f*L.

= 2*3.14*7*1000*15.

= 659.4*1000.

= 660kohms.

Kishan Tj said: (Aug 24, 2012)  
XL=2*PIE*F*L
=2*3.14*7*1000*15
=6.28*7*1000*15
=659.4*1000
=660Kohms

P.Ramachandran said: (Aug 24, 2012)  
1/L=1/L1+1/L2+L3
=1/10+1/10+10
L=1/0.2+10
L= 5+10
L=15H

XL=2*3.14*F*L
=2*3.14*7*15
=659.4KOHM

Girisha P N said: (May 19, 2015)  
XL = 2*Pi*f*L.
L = 15H.
XL = 0.6 Mohm.

Kiran said: (Dec 19, 2016)  
why here 1000 is multiplied with 659.4 ohms?

Puja said: (Jan 14, 2017)  
I don't understand it. Someone explain me in detail.

Raju said: (Jan 25, 2017)  
Frequency has given in kHz so we need to multiply with 1000.

Manish Singh said: (Oct 1, 2017)  
Total inductance=1/(1/10+1/10) +5 =15 H.

Now, total inductive reactance = 2*3.14*f*L = 2*3.14*15*7000 = 660000 ohm (APPROX).

Prashant Kumar said: (Oct 22, 2018)  
XL = 2 *3.143*7*15.
= 660kohm.

Piyush Mishra said: (Jan 18, 2021)  
XL = 2ΠfL = 2*3.14*7000*15 = 659400= That means Approximately 660k ohm.

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