Discussion :: Inductors - General Questions (Q.No.7)
Raja said: (Aug 4, 2011) | |
Can any one explain this why ? |
Asha said: (Oct 3, 2011) | |
L equivalent=15H reactance=wL=2*PIE*F*L |
Shruthi Mathew said: (Jun 18, 2012) | |
1/L(equa) = 1/L1 + 1/L2. L(equa) = 5H. L(equa)+10H = 15H. XL = wL = 2*3.14*f*L = 2*3.14*7*1000*15 = 659.4*1000 = 660kohms. |
Naresh said: (Jun 23, 2012) | |
XL = wL. = 2*3.14*f*L. = 2*3.14*7*1000*15. = 659.4*1000. = 660kohms. |
Kishan Tj said: (Aug 24, 2012) | |
XL=2*PIE*F*L =2*3.14*7*1000*15 =6.28*7*1000*15 =659.4*1000 =660Kohms |
P.Ramachandran said: (Aug 24, 2012) | |
1/L=1/L1+1/L2+L3 =1/10+1/10+10 L=1/0.2+10 L= 5+10 L=15H XL=2*3.14*F*L =2*3.14*7*15 =659.4KOHM |
Girisha P N said: (May 19, 2015) | |
XL = 2*Pi*f*L. L = 15H. XL = 0.6 Mohm. |
Kiran said: (Dec 19, 2016) | |
why here 1000 is multiplied with 659.4 ohms? |
Puja said: (Jan 14, 2017) | |
I don't understand it. Someone explain me in detail. |
Raju said: (Jan 25, 2017) | |
Frequency has given in kHz so we need to multiply with 1000. |
Manish Singh said: (Oct 1, 2017) | |
Total inductance=1/(1/10+1/10) +5 =15 H. Now, total inductive reactance = 2*3.14*f*L = 2*3.14*15*7000 = 660000 ohm (APPROX). |
Prashant Kumar said: (Oct 22, 2018) | |
XL = 2 *3.143*7*15. = 660kohm. |
Piyush Mishra said: (Jan 18, 2021) | |
XL = 2ΠfL = 2*3.14*7000*15 = 659400= That means Approximately 660k ohm. |
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