# Electrical Engineering - Inductors - Discussion

### Discussion :: Inductors - General Questions (Q.No.7)

7.

Two 10 H inductors are in parallel and the parallel combination is in series with a third 10 H inductor. What is the approximate total reactance when a voltage with a frequency of 7 kHz is applied across the circuit terminals?

 [A]. 219 k [B]. 66 k [C]. 660 k [D]. 1.3 M Explanation:

No answer description available for this question.

 Raja said: (Aug 4, 2011) Can any one explain this why ?

 Asha said: (Oct 3, 2011) L equivalent=15H reactance=wL=2*PIE*F*L

 Shruthi Mathew said: (Jun 18, 2012) 1/L(equa) = 1/L1 + 1/L2. L(equa) = 5H. L(equa)+10H = 15H. XL = wL = 2*3.14*f*L = 2*3.14*7*1000*15 = 659.4*1000 = 660kohms.

 Naresh said: (Jun 23, 2012) XL = wL. = 2*3.14*f*L. = 2*3.14*7*1000*15. = 659.4*1000. = 660kohms.

 Kishan Tj said: (Aug 24, 2012) XL=2*PIE*F*L =2*3.14*7*1000*15 =6.28*7*1000*15 =659.4*1000 =660Kohms

 P.Ramachandran said: (Aug 24, 2012) 1/L=1/L1+1/L2+L3 =1/10+1/10+10 L=1/0.2+10 L= 5+10 L=15H XL=2*3.14*F*L =2*3.14*7*15 =659.4KOHM

 Girisha P N said: (May 19, 2015) XL = 2*Pi*f*L. L = 15H. XL = 0.6 Mohm.

 Kiran said: (Dec 19, 2016) why here 1000 is multiplied with 659.4 ohms?

 Puja said: (Jan 14, 2017) I don't understand it. Someone explain me in detail.

 Raju said: (Jan 25, 2017) Frequency has given in kHz so we need to multiply with 1000.

 Manish Singh said: (Oct 1, 2017) Total inductance=1/(1/10+1/10) +5 =15 H. Now, total inductive reactance = 2*3.14*f*L = 2*3.14*15*7000 = 660000 ohm (APPROX).

 Prashant Kumar said: (Oct 22, 2018) XL = 2 *3.143*7*15. = 660kohm.

 Piyush Mishra said: (Jan 18, 2021) XL = 2ΠfL = 2*3.14*7000*15 = 659400= That means Approximately 660k ohm.