Electrical Engineering - Inductors - Discussion

Good @Shoaib.

Thanks @Shoaib.

TIME CONSTANT AND CURRENT RELATIONSHIP:

0 0% of max current.
1Ts 63.2% of max current.
2Ts 86.5% of max current.
3Ts 95% of max current.
4Ts 98.2% of max current.
5Ts 100% of max current.

So, first we know that the maximum possible current through the circuit will be full, means the 100% of max current and the time constant will be 5Ts so,

Time constant => T= (L/R) = (320u/3.3k).
When it reaches max current(100%) it will take 5Ts.
So 5Ts = 5(320u/3.3k),
=0.48us.

Time constant of LR circuit is L/R. So here after multiplying by 5 we get answer is 0.484 micros.

The time required for the current flowing in the LR series circuit to reach its maximum steady state value is equivalent to about 5 time constants or 5T.

This time constant T, is measured by T = L/R, in seconds, were are is the value of the resistor in ohms and L is the value of the inductor in Henries.

Time constant for inductor is L/R.

Why we need to multiply it by 5? How the time taken will be approximately 5T? Why can't it be 10T? Time constant means L/R not LR.

How did you took 5T? Please explain it.

Time constant for RL circuit is L/R SO time constant = (320*10^(-6)/3.3*10^(3)) time taken to reach final value is approximately 5T = 0.48*10^(-6).

What is time constant?