Electrical Engineering - Inductors - Discussion

Discussion :: Inductors - General Questions (Q.No.22)

22. 

The following coils are in parallel: 75 H, 40 H, 25 H, and 15 H. The total inductance is approximately

[A]. 6.9 H
[B]. 14 H
[C]. 2.2 H
[D]. 155 H

Answer: Option A

Explanation:

No answer description available for this question.

Vandan said: (Aug 30, 2011)  
Total inductance = Lp

and

1/Lp=1/L1 + 1/L2 + 1/L3 + 1/L4

Here L1, L2, L3, L4 are 75, 40, 25, 15.

Biresh said: (Feb 10, 2012)  
1/75+1/40+1/25+1/15

Parneet Kaur said: (Jul 11, 2015)  
Can anybody solve this sum in detail?

Arun Kumar M said: (Aug 22, 2015)  
1/L = 1/L1+1/L2+1/L3+1/L4.

1/L = 1/75+1/40+1/25+1/15.
1/L = 0.013+0.025+0.04+0.066.

1/L = 0.144.

L = 1/0.144.
L = 6.9.

Mukhtar said: (Sep 9, 2015)  
Same formula as that of the resistors when connected in parallel.

Arjun said: (Jan 13, 2017)  
75||40 = 26.08.
25||15 = 9.375.
26.08||9.375 = 6.9.

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