### Discussion :: Inductors - General Questions (Q.No.20)

Prasanthi Rao said: (Sep 17, 2011) | |

The inductances values are 8,16,32,64,128 Therefore total inductance connected in series = 8+16+32+64+128 = 248 |

Nt- said: (Oct 25, 2014) | |

Or you could realize that you have a geometric series with 5 terms and use the formula. s = a* (1-r^n) / (1-r) where in this case a is 8 uH, n is 5, and R is 2. |

D.Ramesh said: (Dec 22, 2016) | |

Total inductance = L1 + L2 + L3 + L4 + L5. L1 = 8 L2 = 16 L3 = 32 L4 = 64 L5 = 128. 8 + 16 + 32 + 64 + 128 = 248. |

Srikanth said: (Jun 15, 2017) | |

Yes, correct @D.Ramesh. |

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