Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 14)
14.
The current through a 120 mH coil is changing at a rate of 150 mA/s. The voltage induced across the coil is
Discussion:
8 comments Page 1 of 1.
Yaganti eswar said:
3 years ago
Can you explain about resistance and inductance difference.
Chandini said:
6 years ago
Clearly said, thanks @Gangadhar.
Gangadhar said:
7 years ago
V = L * (di/dt) = (120 * 150)m * m =18000 m * m =18mv.
(1)
Vivek Singh said:
9 years ago
@Suryankya : your answer is right because we take all quantity in same before solving the problem.
John said:
9 years ago
@Suryankya.
The answer should be 0.018v, not 0.0018v.
The answer should be 0.018v, not 0.0018v.
Pavittar said:
10 years ago
Both are right.
Suryankya said:
1 decade ago
The inductance is 120 mH = 120*10^-3H.
The current is 150 mA/sec =150*10^-3A/sec.
V = L(di/dt).
= (120*10^-3)*(150*10^-3).
= 0.0018v.
The current is 150 mA/sec =150*10^-3A/sec.
V = L(di/dt).
= (120*10^-3)*(150*10^-3).
= 0.0018v.
S.Senbagarajan said:
1 decade ago
Given datas
The inductance is 120mH
The current is 150mA/s
V=L*(di/dt)
L=120*10^-3=0.120
V=0.120*150
so
V=18mV
The inductance is 120mH
The current is 150mA/s
V=L*(di/dt)
L=120*10^-3=0.120
V=0.120*150
so
V=18mV
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers