# Electrical Engineering - Inductors - Discussion

### Discussion :: Inductors - General Questions (Q.No.14)

14.

The current through a 120 mH coil is changing at a rate of 150 mA/s. The voltage induced across the coil is

 [A]. 1.8 mV [B]. 18 mV [C]. 180 mV [D]. 1.25 mV

Explanation:

No answer description available for this question.

 S.Senbagarajan said: (Aug 31, 2011) Given datas The inductance is 120mH The current is 150mA/s V=L*(di/dt) L=120*10^-3=0.120 V=0.120*150 so V=18mV

 Suryankya said: (Sep 5, 2013) The inductance is 120 mH = 120*10^-3H. The current is 150 mA/sec =150*10^-3A/sec. V = L(di/dt). = (120*10^-3)*(150*10^-3). = 0.0018v.

 Pavittar said: (Nov 21, 2015) Both are right.

 John said: (May 5, 2016) @Suryankya. The answer should be 0.018v, not 0.0018v.

 Vivek Singh said: (Sep 9, 2016) @Suryankya : your answer is right because we take all quantity in same before solving the problem.

 Gangadhar said: (Dec 21, 2018) V = L * (di/dt) = (120 * 150)m * m =18000 m * m =18mv.

 Chandini said: (Jan 31, 2020) Clearly said, thanks @Gangadhar.