Electrical Engineering - Inductors - Discussion

Discussion :: Inductors - General Questions (Q.No.14)

14. 

The current through a 120 mH coil is changing at a rate of 150 mA/s. The voltage induced across the coil is

[A]. 1.8 mV
[B]. 18 mV
[C]. 180 mV
[D]. 1.25 mV

Answer: Option B

Explanation:

No answer description available for this question.

S.Senbagarajan said: (Aug 31, 2011)  
Given datas
The inductance is 120mH
The current is 150mA/s

V=L*(di/dt)
L=120*10^-3=0.120
V=0.120*150
so
V=18mV

Suryankya said: (Sep 5, 2013)  
The inductance is 120 mH = 120*10^-3H.

The current is 150 mA/sec =150*10^-3A/sec.

V = L(di/dt).

= (120*10^-3)*(150*10^-3).

= 0.0018v.

Pavittar said: (Nov 21, 2015)  
Both are right.

John said: (May 5, 2016)  
@Suryankya.

The answer should be 0.018v, not 0.0018v.

Vivek Singh said: (Sep 9, 2016)  
@Suryankya : your answer is right because we take all quantity in same before solving the problem.

Gangadhar said: (Dec 21, 2018)  
V = L * (di/dt) = (120 * 150)m * m =18000 m * m =18mv.

Chandini said: (Jan 31, 2020)  
Clearly said, thanks @Gangadhar.

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