Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 6)
6.
A sine wave voltage is applied across an inductor. When the frequency of the voltage is decreased, the current
Discussion:
21 comments Page 2 of 3.
Bhargav said:
9 years ago
Frequency decreased means time period increases. Hence voltage decreases. Therefore current decreases.
(1)
D Shwetha said:
7 years ago
@Sumeet.
Your explanation is good.
I=V/XL,
I=V/2πfL,
If Frequency decrease, I will increase.
Your explanation is good.
I=V/XL,
I=V/2πfL,
If Frequency decrease, I will increase.
(3)
Shivu said:
6 years ago
Current will remains the same, because inductor which opposes the change of current.
Rafiq said:
9 years ago
Current increases because it is inversely proportion to the inductive reactance.
MD JAMSHED NAUSHERWAN said:
1 decade ago
I=v/Xl, so XL=6. 8fl, thats why frequency reducing current will be increased.
Abdul Rauff said:
1 decade ago
Xl = jwL = j*2*pi*f*L
so when f decreases ,Xl decreases and current increase
so when f decreases ,Xl decreases and current increase
Santosh kumar said:
1 decade ago
When frequency decrease indultance also decrease and so current increase.
Kamlesh yadav said:
8 years ago
Here, f proportional to V/I.
Then f decreases with increases I.
Then f decreases with increases I.
Abbas said:
5 years ago
If xl= 2p then it will increases.
Albert said:
8 years ago
Yes, You are right @Bhargav.
(1)
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