Electrical Engineering - Inductors - Discussion

Under transient condition (Here:-closing of switch) inductor behaves like open circuit so voltage across inductor is 6.

After than current in the circuit gradually increase and after finite time inductor behaves short circuit so that voltage across it 0.

For DC source inductor act as sort circuit the voltage is zero.

Though it is DC source. At 0 instant the voltage will bot be 6 V.

The voltage has to raise from 0 to 6 volts, which is change in voltage. This change is not acceptable by the inductor. Hence initially the inductor acts as a open circuit.

Why any current dropage is not there? There is one resistor is connected.

The inductor property is opposes to sudden changing current does not opposes voltage so total voltage appear across it.

I agree with @Soumya sen. Here we're considering transient condition. Thus inductor is open. Hence voltage across inductor is 6V. Current=0 ==>voltage drop across resistor is 0.

Here we are dealing with transient conditions. Hence answer is 6V.

An inductor is does not allow sudden change in only current so voltage is supply voltage.

Yes.

In case of AC. Above answer is right as current cannot change instantaneously due to impedance.

But here battery is DC. Here inductor will act as a conductor (just like resistor). No ideal inductor exists. Ideal condition can be taken only for theoretical calculation as well as simulation purpose.

In real time. Inductor will offer some finite resistance to drop the voltage like resistor.

Since we have no idea about finite resistance in inductance. Hence we assume ideal condition 0V.

Voltage drop = 0.

In DC network inductor works as short path. So no drop here.

The final answer is 0.0V.