Electrical Engineering - Inductors - Discussion

Why any current dropage is not there? There is one resistor is connected.

At t=0 inductor behave as open ckt and 6v dro across it.

Then what is the volt across resister?

As the nature of inductor is to oppose the change of current through it, it initially opposes the current flow through it. Thereby it acts as an open circuit. & total drop appears at inductor.

For dc inductor acts as a short cicuit. So voltage across inductor is zero.

Then how the voltage across inductor is 6v?

My first answer is also zero, but if you follow the principle behind resistance in series connection, V1=V2=V3=Vn, so 6v=voltage in resistor=voltage in inductor.

Voltage drop = 0.

In DC network inductor works as short path. So no drop here.

The final answer is 0.0V.

Yes.

In case of AC. Above answer is right as current cannot change instantaneously due to impedance.

But here battery is DC. Here inductor will act as a conductor (just like resistor). No ideal inductor exists. Ideal condition can be taken only for theoretical calculation as well as simulation purpose.

In real time. Inductor will offer some finite resistance to drop the voltage like resistor.

Since we have no idea about finite resistance in inductance. Hence we assume ideal condition 0V.

An inductor is does not allow sudden change in only current so voltage is supply voltage.

Here we are dealing with transient conditions. Hence answer is 6V.