Discussion :: Inductors - General Questions (Q.No.21)
| Kirthikumar Rao said: (Nov 23, 2011) | |
| Wkt LI=NQ L=inductance of the coil I=current N=no of turns of the coil Q=flux as inductance is directly proportional to no of turns |
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| Deep Sandholia said: (Nov 26, 2013) | |
| Flux is directly proportional to no.of turns. | |
| Dipak said: (Dec 2, 2014) | |
| L = N^2/R. L = INDUCTANCE. N = NUMBER OF TURNS. R = RELUCTANCE OF CORE. |
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| Eng. S.T.Arif said: (Apr 29, 2015) | |
| Inductance (Physical property of a coil) L = U.N2.l.A. U = Permeability of core, N2 = NxN (Number of turns). L = Length of coil. A = Cross sectional area of coil. So if to decrease L. You decrease (remove of iron core). Reduce N turns of coil. Reduce length of coil. The correct answer is not given in the question. |
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| Sandeshg said: (Jun 11, 2015) | |
| Answers A, B are correct. Air core has less permittivity as compared to iron core hence lesser the permittivity lesser the inductance of the coil. | |
| Svn said: (Jan 9, 2017) | |
| Right answer is both A and B. | |
| Deepak said: (Jan 19, 2018) | |
| Here, L=£N^2A/L. | |
| Haris said: (Jan 11, 2020) | |
| L = (permiability)*(no of turns)^2*Area/Length. L = u*N^2 * A/length. |
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