Electrical Engineering - Inductors - Discussion
Discussion Forum : Inductors - General Questions (Q.No. 21)
21.
The inductance of an iron-core coil decreases if
Discussion:
8 comments Page 1 of 1.
HAris said:
6 years ago
L = (permiability)*(no of turns)^2*Area/Length.
L = u*N^2 * A/length.
L = u*N^2 * A/length.
Deepak said:
8 years ago
Here, L=£N^2A/L.
Svn said:
9 years ago
Right answer is both A and B.
Sandeshg said:
1 decade ago
Answers A, B are correct. Air core has less permittivity as compared to iron core hence lesser the permittivity lesser the inductance of the coil.
Eng. S.T.Arif said:
1 decade ago
Inductance (Physical property of a coil) L = U.N2.l.A.
U = Permeability of core,
N2 = NxN (Number of turns).
L = Length of coil.
A = Cross sectional area of coil.
So if to decrease L.
You decrease (remove of iron core).
Reduce N turns of coil.
Reduce length of coil.
The correct answer is not given in the question.
U = Permeability of core,
N2 = NxN (Number of turns).
L = Length of coil.
A = Cross sectional area of coil.
So if to decrease L.
You decrease (remove of iron core).
Reduce N turns of coil.
Reduce length of coil.
The correct answer is not given in the question.
DIPAK said:
1 decade ago
L = N^2/R.
L = INDUCTANCE.
N = NUMBER OF TURNS.
R = RELUCTANCE OF CORE.
L = INDUCTANCE.
N = NUMBER OF TURNS.
R = RELUCTANCE OF CORE.
Deep sandholia said:
1 decade ago
Flux is directly proportional to no.of turns.
Kirthikumar rao said:
1 decade ago
Wkt LI=NQ
L=inductance of the coil
I=current
N=no of turns of the coil
Q=flux
as inductance is directly proportional to no of turns
L=inductance of the coil
I=current
N=no of turns of the coil
Q=flux
as inductance is directly proportional to no of turns
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