Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 17)
17.
A 220 
resistor dissipates 3 W. The voltage is
resistor dissipates 3 W. The voltage isDiscussion:
7 comments Page 1 of 1.
D. Mallikarjun said:
9 years ago
P Vxl.
P VxV/R.
3w = v^2/22O.
V^2 = 660,
V = √ 660,
V = 25.690v.
P VxV/R.
3w = v^2/22O.
V^2 = 660,
V = √ 660,
V = 25.690v.
Bereket said:
10 years ago
p = v*i but; v = i*r.
Hence p = i*i*r.
p = i^2*r.
3w = i^2*220.
Then i^2 = 3w/220.
I^2 = 0.01363636.
Out of square root is correct answer.
Hence p = i*i*r.
p = i^2*r.
3w = i^2*220.
Then i^2 = 3w/220.
I^2 = 0.01363636.
Out of square root is correct answer.
Ladcode said:
10 years ago
220*3 = 660.
Square root 660 = 25.69.
Square root 660 = 25.69.
(1)
Ezeihejafor emmanuel said:
1 decade ago
If you don't use calculator that means you will use log table.
v^2 = 660 therefor v = 660^1/2 making v = 1/2 log 660.
Then use logarithm table to simplify further.
Keep 1/2 constant look for log of 6 under 6 difference 0, compute and get the anti log. Put your point and then multiply by 1/2 and get your answer.
v^2 = 660 therefor v = 660^1/2 making v = 1/2 log 660.
Then use logarithm table to simplify further.
Keep 1/2 constant look for log of 6 under 6 difference 0, compute and get the anti log. Put your point and then multiply by 1/2 and get your answer.
Harsha said:
1 decade ago
How to calculate without calculator v^2=660?
(1)
DARSHAN said:
1 decade ago
power P=V*I
P=V*(V/R)
3=V^2/220
V^2=660
V=25.690 VOLT
v =25.7 VOLT
P=V*(V/R)
3=V^2/220
V^2=660
V=25.690 VOLT
v =25.7 VOLT
(2)
Krish said:
1 decade ago
power = v^2/r
hence, 220 = v^2/3
or, sqrt(660) = v
therefore, v = 25.693 volts.
hence, 220 = v^2/3
or, sqrt(660) = v
therefore, v = 25.693 volts.
(1)
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