Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 16)
16.
For 12 V and 40 mA, the power is
480 mW
0.480 W
480,000 µW
all of the above
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
7 comments Page 1 of 1.

Narayandas Karthik said:   1 year ago
Anyone give us a clear Explanation for the answer.

Bempah said:   5 years ago
P= I*V.
P =(0. 04) *12,
P= 0.48W.

Conversions:
0.48W=480mW=480,000uW.

Hence D is the answer.
(1)

Kunjan said:   9 years ago
P = i * i * R,
i = .040A,
R = V/i,
R = 12/.040,
R = 300,
P = .040 * .040 * 300,
P = .480W.

And same as,

P = 480mW,
P = 480000 micro watt.

Akash said:   1 decade ago
Solution:

Voltage (v) = 12v.
Current (i) = 40mA.
Power = voltage*current.
Power = 12*40 = 480mWatts = 0.480w = 480000µW.

Atanu biswas said:   1 decade ago
@ sabarinathan, u r wrong.
40mA=0.04A
then how can u multiply 12 with 40?

0.48w=480mW(MEGA WATT)=480,000uW.
all of the above.

Sabarinathan said:   1 decade ago
p = i x v

= 12 x 40

= 480w

= 480/1000

p = 0.48

Answere is D.

Krishnan said:   1 decade ago
Power = 12/(40/1000)
= 0.48 w

all the values are correct

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