Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 14)
14.
If it takes 400 ms to use 12,000 J of energy, the power is
Discussion:
6 comments Page 1 of 1.
Manimaran said:
1 decade ago
j= w*s
w=j/s=12000/.4 = 30kw
w=j/s=12000/.4 = 30kw
Manish said:
1 decade ago
Energy E = P*T
E/T = P
12000/400*10^-3 = P
30*10^3 = P
30000W = P
So ans is 30KW
E/T = P
12000/400*10^-3 = P
30*10^3 = P
30000W = P
So ans is 30KW
Pranay said:
1 decade ago
Here we have J = 12000 and ms = 400
Now its a formula watt.sec = joules
So, watt = joules/sec
watt = 12000/400ms = 30000 watt = 30kw
Now its a formula watt.sec = joules
So, watt = joules/sec
watt = 12000/400ms = 30000 watt = 30kw
Pooja jaiswal said:
1 decade ago
E = P*T.
So, P = E/T.
= 12000/4*0.001.
= 30KW
So, P = E/T.
= 12000/4*0.001.
= 30KW
(1)
Akash said:
1 decade ago
Solution:
Total charge = 12000J.
Time of period = 400milli sec = 0.4sec.
Power = Charge(Q)/Time(t).
Power = 12000/0.4 = 30000 Watts.
Power in kw = 30000/1000 = 30KW.
Total charge = 12000J.
Time of period = 400milli sec = 0.4sec.
Power = Charge(Q)/Time(t).
Power = 12000/0.4 = 30000 Watts.
Power in kw = 30000/1000 = 30KW.
(3)
Amit ranjitkar said:
1 decade ago
Energy = Power*Time.
Power = Energy/Time.
Power = 12000/0.400.
= 30000 watt.
= 30 kw.
Power = Energy/Time.
Power = 12000/0.400.
= 30000 watt.
= 30 kw.
(2)
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