Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 7)
7.
A 15 V source is connected across a 12 
resistor. How much energy is used in three minutes?
resistor. How much energy is used in three minutes?Discussion:
32 comments Page 3 of 4.
Naser said:
1 decade ago
15*15/12 = 18.75.
18.75/60 = 0.3125.
0.3125*3 = 0.9375 wh.
18.75/60 = 0.3125.
0.3125*3 = 0.9375 wh.
Sudip said:
1 decade ago
P=VI
P=15*1.25=18.75
Total power = 18.75*3/60= .937
P=15*1.25=18.75
Total power = 18.75*3/60= .937
Tejswee said:
1 decade ago
Energy = Power*Time = (i^2*r)*(3/60) = 0.9375
(1)
Anonymous said:
1 decade ago
Why can't we use the formula V^2/R*t?
Zahid said:
10 years ago
Well said @Bains and @Debu.
Gaikwad.pravin said:
8 years ago
Here, it is (v^2/R) *3.
Ravi26v said:
2 decades ago
((V*V)/ R)*time in hrs
Satish mahadu kukade said:
9 years ago
You are correct @Debu.
Pankaj R.Patil said:
1 decade ago
v^2/r*t, t in hours.
Muhammad Fayyaz said:
2 decades ago
@Ravi26v is right.
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