Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 7)
7.
A 15 V source is connected across a 12 resistor. How much energy is used in three minutes?
938 Wh
0.938 Wh
56.25 Wh
5.6 Wh
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
31 comments Page 2 of 4.

BIPRADAS GHOSH said:   1 decade ago
Energy = (I)2Rt.

I = V/R = 15/12 = 1.25.

R = 12 and t = 3 min = 3/60 hr = 0.05 hr.

So, Energy = (1.25)2*12*0.05 = 0.9375.

Bibek said:   7 years ago
we know that, E=i*i* R *T.
I=V/R =15/12=1.25 A,
T=3 MIN,
60 MIN=1 HOUR,
3MIN=3/60 HOUR=.05 H.
E=1.25*1.25*12*.05=0.9375 Wh.

ARAMUTHAN said:   1 decade ago
Energy = Power x time (V=IR)--I = 15 V/12Ohms = 19.5

Energy = (1.25*15) x 3

Energy = 56.25 Wh so the answer should be C

Naresh Jadav said:   1 decade ago
Let,

3 minite = 0.05h.

I = V/R.

=15/12 = 1.25 A.

Power = V*I = 12*1.25 = 18.75w.

Now,

W*h = 18.75*0.05 = 0.9375wh.

Debu said:   1 decade ago
15v/12=1.25amps P=VI = 15*1.25=18.75W consumed in one hour So in 3 minute 3/60=.05 POWER IN THREE MINUTE=.05*18.75=.9375

BAINS said:   1 decade ago
15v/12=1.25amps P=VI = 15*1.25=18.75 , FOR TIME IN MINUTE 3/60=.05 POWER IN THREE MINUTE=.05*18.75=.9375

Kgabisang said:   8 years ago
v=IR
I=V/R
=15V/12ohm
=1.25A.

P=VI
=15V * 1.25A
= 18.5W.

Energy = Power * time
=18.75W * 0.05h
=0.938 Wh.
(7)

RAVI said:   1 decade ago
15/12 = 1.25 A.

3/60 = 0.05 H.

P = 15*1.25 = 18.75 W.

E = 18.75*0.05 = 0.9375 WH.

Mrakovic said:   1 decade ago
W = U^2/R.

W = 225/12 = 18.75W.

3 min = 0.05h.

Wh = W*t = 18.75*0.05 = 0.9375Wh.

Naser said:   1 decade ago
15*15/12 = 18.75.
18.75/60 = 0.3125.
0.3125*3 = 0.9375 wh.


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