Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 23)
23.
A 75 
load uses 2 W of power. The output voltage of the power supply is approximately
load uses 2 W of power. The output voltage of the power supply is approximatelyDiscussion:
4 comments Page 1 of 1.
Zabi Ullah Mir said:
5 years ago
P=v^2/R)))))). V= √(p*R).
(1)
Mohamed Atnan said:
6 years ago
V = √ (P*R),
V = √ (2*75),
V = √ (150),
V = 12.24.
V = √ (2*75),
V = √ (150),
V = 12.24.
Manish said:
1 decade ago
Power P = I^2*R
I^2 = P/R
I^2 = 2/75 =0.02666
I = Squroot of(0.02666)
I = 0.163A
Theoutput Voltage V = IR
V = 0.163*75
V = 12.2V
So The Ans is Approximately 12 V.
I^2 = P/R
I^2 = 2/75 =0.02666
I = Squroot of(0.02666)
I = 0.163A
Theoutput Voltage V = IR
V = 0.163*75
V = 12.2V
So The Ans is Approximately 12 V.
Hari said:
1 decade ago
p=v*v/r
i.e v=sqrt(p*r)
=sqrt(75*2)
=sqrt(150)
This is the correct answer
Aproximately it is equal to 12
i.e v=sqrt(p*r)
=sqrt(75*2)
=sqrt(150)
This is the correct answer
Aproximately it is equal to 12
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