Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 11)
11.
A 6 V battery is connected to a 300 
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?Discussion:
23 comments Page 2 of 3.
Bhupendra kumar marwal said:
1 decade ago
The unit of load is not given therefore the load should actually be considered to be 300w in place of 300ohm.
Suri said:
7 years ago
V=I x R.
6V=I x 300ohms.
I=6V / 300ohms.
I=0.02Amps.
40Amps-hour / 0.02Amps = 2000 hours.
2000 Hours Answer.
6V=I x 300ohms.
I=6V / 300ohms.
I=0.02Amps.
40Amps-hour / 0.02Amps = 2000 hours.
2000 Hours Answer.
Sabir said:
8 years ago
Energy E = V * Q = V * IT = 6 * 40 = 240WH.
POWER P=VI=Vsqr /R =.12W,
E = P * T,
T = E/P = 2k.
POWER P=VI=Vsqr /R =.12W,
E = P * T,
T = E/P = 2k.
Aniket said:
1 decade ago
What is the relation between current and frequency?
Which is quantity that is measured in h?
Which is quantity that is measured in h?
Rajakumar said:
6 years ago
Current through load I=V/R.
I=6/300=0.02 then,
Rating=40AH,
40=0.02H.
So, Duration H=2000.
I=6/300=0.02 then,
Rating=40AH,
40=0.02H.
So, Duration H=2000.
(1)
Shahid said:
4 years ago
V/R =6/300 =0.02A
Load time = Battery Capacity in Ah/Load Current.
= 40Ah/.02A = 2000h.
Load time = Battery Capacity in Ah/Load Current.
= 40Ah/.02A = 2000h.
(7)
Shweta said:
1 decade ago
I = V/R.
= 6/300.
= 0.02A.
Ah = 40.
H = 40/A.
= 40/0.02.
= 2000.
= 6/300.
= 0.02A.
Ah = 40.
H = 40/A.
= 40/0.02.
= 2000.
(1)
Chaitanya said:
1 decade ago
ih=40.
i=v/r
we knw v=6 n r=300
sub in 1st eqn we get h=2000
i=v/r
we knw v=6 n r=300
sub in 1st eqn we get h=2000
LKI said:
1 decade ago
P=VI
E=P*t
I=V/R=6/300=.02A
40=.02*t
t=40/.02=2000h
E=P*t
I=V/R=6/300=.02A
40=.02*t
t=40/.02=2000h
Hawks_xavier said:
1 decade ago
Ans = 40/0.02(current through 300Ohms Load)
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