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Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 11)
Energy and Power
11.
A 6 V battery is connected to a 300 load. Under these conditions, it is rated at 40 Ah. How long can it supply current to the load?
1 h
200 h
2,000 h
10 h
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
23 comments Page 2 of 3.
Sabir said:   8 years ago
Energy E = V * Q = V * IT = 6 * 40 = 240WH.
POWER P=VI=Vsqr /R =.12W,
E = P * T,
T = E/P = 2k.
Rajajee said:   1 decade ago
In the above problem given ah=40 and we get i from v=i*r as 0.02.

So in ah=40 amp a=0.02, So .02*h=40.

h=40/0.02=2000.
Aniket said:   1 decade ago
What is the relation between current and frequency?

Which is quantity that is measured in h?
Bhupendra kumar marwal said:   1 decade ago
The unit of load is not given therefore the load should actually be considered to be 300w in place of 300ohm.
Nick said:   1 decade ago
I=V/R=6/300=0.02A
T=40Ah/0.02A=2000h
Ashraf said:   1 decade ago
Energy produce by battery = 40*6 = 240whr

Power taken by load = v*v/r = 0.12

So current supplying time = 240/.12=2000hr
Upendra said:   1 decade ago
Actually current taken by 300ohm load is 6/300=0.02Amp. If condition saying,battery is under 40AH then to cover 40Amps, load has to take 2000hr at a constant current of 0.02Amps.

So answer is 'C'.
Phani bhargav.v said:   1 decade ago
Actually load may be or may not be estimate like this as 300 ohms, why because power consumption is depend upon their capacity in fact their wattage.
Chaitanya said:   1 decade ago
ih=40.
i=v/r
we knw v=6 n r=300
sub in 1st eqn we get h=2000
Md. Muin Uddin said:   1 decade ago
Energy produce by battery = 40*6 = 240whr

Power taken by load = v*v/r = 0.12

So current supplying time = 240/.12=2000hr.
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