Electrical Engineering - Energy and Power - Discussion
Discussion Forum : Energy and Power - General Questions (Q.No. 9)
9.
A 120 
resistor must carry a maximum current of 25 mA. Its rating should be at least
resistor must carry a maximum current of 25 mA. Its rating should be at leastDiscussion:
59 comments Page 5 of 6.
Himansu said:
1 decade ago
Answer should be 75mW. It should be verified.
Stuti kushwaha said:
10 years ago
Irms = 25.
Im = (25*1.414)^2*12 = 150 mA.
Im = (25*1.414)^2*12 = 150 mA.
Supriyo said:
9 years ago
I too think 75mw is the correct answer.
Bibek said:
7 years ago
I think 75 mW is the correct answer.
RAJESH BANOTH said:
1 decade ago
p=i2r
=2*(25*10-3)2*120
=150mw
=2*(25*10-3)2*120
=150mw
Ravindranarayan said:
9 years ago
Yes, 75mw is the correct answer.
Pratik suhas gajengi said:
9 years ago
You are right @R N Trimukhe.
Prasad said:
10 years ago
Rating of resistor = 2VI.
Suresh said:
1 decade ago
@Pankaj ahuja is correct.
Biswa said:
1 decade ago
i^2*r
=.025*.025*120=75mw
=.025*.025*120=75mw
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