Electrical Engineering - Energy and Power - Discussion

Discussion Forum : Energy and Power - General Questions (Q.No. 9)
9.
A 120 resistor must carry a maximum current of 25 mA. Its rating should be at least
4.8 W
150 mW
15 mW
480 mW
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
60 comments Page 2 of 6.

Hemant said:   9 years ago
Rated value means the device should operate that value. Here, 75mW is the right answer. We can't say the rated value is 150mW as per the formula.

Ravindranarayan said:   9 years ago
Yes, 75mw is the correct answer.

Stuti kushwaha said:   10 years ago
Irms = 25.

Im = (25*1.414)^2*12 = 150 mA.

PRITAM said:   10 years ago
The answer should be 75 mw because which is not in option. Some of guys have said that it will be 150 mw. How if you really did then I think you must solved after seeing an option?

Rkn said:   1 decade ago
How could 150mW be correct answer. It is clear from the question that for a power rating beyond 75mW the resistor's characteristics will be altered.

So the maximum rating is 75mW and among options only 15mW is less than this value. So the answer should be 15mW. Anyway a 20W rated doesn't burn out at this value.

Ravi said:   1 decade ago
Formula:

Irms = Im\root2 then Im = Ir*root2.

Im value is = 25 mA*root2 = 0.03536 A.

Then P = I*I*R = 0.03536*0.03536*120 = 150 mW.

Prasad said:   1 decade ago
Rating of resistor = 2VI.

Rishipal said:   9 years ago
D is correct because maximum current is given it is not RMS current so, it changes in RMS current.

RMS current=maximum current/root2. Then power = i2r.

Ashish said:   1 decade ago
How answer is 150?

Sandy said:   1 decade ago
Current = 25 ma = 0. 025 a.

Voltage = ?

Resistor = 120 ohm.

I = v/r.
v = ir.
v = 0.025*120 = 3 v.

p = vi.
p = 3*0.025 = 0.075 w = 75 mw.


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