Electrical Engineering - Circuit Theorems in AC Analysis - Discussion

Discussion Forum : Circuit Theorems in AC Analysis - General Questions (Q.No. 7)
7.
Referring to the given figure, determine ZTH as seen by RL if R1 is changed to 3.3 k.

1488–70.7°
3859 –31.2°
5180 –50.5°
1828–50.2°
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
6 comments Page 1 of 1.

Praveen said:   1 decade ago
Since the frequency given is 0, impedances of the capacitors are infinite (acts as open circuit). So Zth is infinite.
(1)

Ashoka J said:   1 decade ago
Yes Option D is correct.

Zeq 1 = 3.3+j2 = 3.86(-31.28' k ohm.)

Zeq 2 = Zeq 1 parallel with Xc2 = 3.86(-31.28*2)(-90/3.86)(-31.28+2)(-90) = 1.488(-70.8' k ohm.)

Zth = 1488(-70.7+6800) = 1829(-50.1' ohm.)

Or 1717-j1404 ohm.
(1)

John said:   6 years ago
Don't forget that in Capacitor circuit we could have,
Z=R-jXc, Hence the negative angle is correct.
(1)

Althaf said:   1 decade ago
R1 and XC1 are in series = let it be Req1.

Req1||XC2 = Req2.

Req2+r2 = Zth.

Izhar Ahmed said:   6 years ago
According to me, the answer 1828*angle(+50.2°) not -50.2.


Please Explain.

Joesmarti said:   3 years ago
Here, Z= ((R1+XC1)||XC2) + R2.

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