Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 6)
6.
Determine IN for the circuit consisting of VS, R1, R2, and R3 shown in the given circuit.
Discussion:
20 comments Page 2 of 2.
Tes said:
1 decade ago
I think you should use thevnin theorem. That means find Vn by opening AB and find Rn by shorting AB. Finally divide Vn / Rn = In.
Dishant said:
1 decade ago
It's simple. Just short AB & apply kvl.
ASHISH NAUTIYAL said:
1 decade ago
From nodal equation.
(v-75)/68+v/68+v/120 = 0.
By solving this we get v = 29.22.
Now by ohm's law to 120 ohm resistor.
IN = v/r = 29.22/120 = 0.244A.
or 1A = 1000mA.
SO, 0.244*1000 = 244mA.
(v-75)/68+v/68+v/120 = 0.
By solving this we get v = 29.22.
Now by ohm's law to 120 ohm resistor.
IN = v/r = 29.22/120 = 0.244A.
or 1A = 1000mA.
SO, 0.244*1000 = 244mA.
Mathireesan said:
1 decade ago
IN means?
Jeffrey said:
1 decade ago
It means Norton Current.
(1)
Sankararao mamidi said:
1 decade ago
Apply nodal equation to the circuit.
[v-75]/68+v/68+v/120 = 0.
We get v = 29.22.
In = v/r.
In = 29.22/120.
In = 0.2435A.
[v-75]/68+v/68+v/120 = 0.
We get v = 29.22.
In = v/r.
In = 29.22/120.
In = 0.2435A.
(3)
Ankur said:
10 years ago
It can be solved by Thevenin's theorem. But have to ignore value of RL in equation. IL = vth/Rth+RL.
(1)
Prosper said:
8 years ago
RL represent the Load, using nortons theorem, you remove the load and find the current through R3.
Paresh khatri said:
8 years ago
IN means Norton current.
(3)
Akshaykumar said:
6 years ago
Apply KCL to both loop, then solve those two equations, then the current i2 will be the answer, i.e=0.436A.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers