Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 11)
11.
What is the Thevenin equivalent (VTH and RTH) for the circuit given?
6.4 V, 422 
6.4 V, 560
6.4 V, 680
30 V, 422
Discussion:
13 comments Page 1 of 2.
Azeem said:
5 years ago
Rth = R1||R2 + R3||R4 = 422.
Vth = Va-Vb.
Va = R2/(R1+R2)*Vs = 22.666.
Vb = R4/(R3+R4)*Vs = 16.31.
Vth = 6.356 V.
Vth = Va-Vb.
Va = R2/(R1+R2)*Vs = 22.666.
Vb = R4/(R3+R4)*Vs = 16.31.
Vth = 6.356 V.
(6)
Praveen said:
6 years ago
Thanks for explaining it.
(1)
Pkgp said:
7 years ago
Thank you all.
Prashant said:
8 years ago
Thanks @Aswathy.
Shan said:
9 years ago
Vth is 6.28.
Use vlt divider rule.
Use vlt divider rule.
Akhila said:
9 years ago
Well said, Thank you all.
Aswathy said:
9 years ago
Rth = (R1 // R2) + ( R3 // R4).
= 220||680 + 470||560 = 421.75 (422).
Vth is the open circuited voltage therefore find the effective resistance neglecting RL
R eff = R1 + R2 II R3 + R4.
= 220 + 680 II 560 + 470 = 900 II 1030= (900 * 1030) /(900 + 1030) = 480.31.
Now find the total current.
I = V/Reff =30/480.31 = 0.062.
Find current through each parallel branch using current division:
I1 = (0.062 * 1030)/(1030 + 900) = 0.033.
I2 = 0.062 - 0.033 = 0.029.
Vth= VA - VB = V470 - V220.
=(470 * 0.029) - (220 * 0.033) = 6.37 v.
= 220||680 + 470||560 = 421.75 (422).
Vth is the open circuited voltage therefore find the effective resistance neglecting RL
R eff = R1 + R2 II R3 + R4.
= 220 + 680 II 560 + 470 = 900 II 1030= (900 * 1030) /(900 + 1030) = 480.31.
Now find the total current.
I = V/Reff =30/480.31 = 0.062.
Find current through each parallel branch using current division:
I1 = (0.062 * 1030)/(1030 + 900) = 0.033.
I2 = 0.062 - 0.033 = 0.029.
Vth= VA - VB = V470 - V220.
=(470 * 0.029) - (220 * 0.033) = 6.37 v.
(1)
Nami said:
10 years ago
What about vth then?
(3)
Naveedabanu said:
1 decade ago
I agree with answers. But I am not getting series and parallel combination. Please tell me if you know.
SHASHI said:
1 decade ago
R1 parallel to R2& R3 is parallel to R4 and the result of R1||R2&R3||R4 are in series.
= 220||680+470||560 = 421.75 (422).
= 220||680+470||560 = 421.75 (422).
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