Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 1)
1.
Find the Thevenin equivalent (VTH and RTH) between terminals A and B of the circuit given below.
4.16 V, 120 
41.6 V, 120
4.16 V, 70
41.67 V, 70
Discussion:
42 comments Page 4 of 5.
N.Vinoth kumar said:
1 decade ago
R1+R2+R3=R
I=V/R
Vth=IR
Rth= (R1+R2)/R3
I=V/R
Vth=IR
Rth= (R1+R2)/R3
Sourav Sau said:
1 decade ago
By voltage devider rule Vth= 120*100/68+100+120
Nd Rth= (R1+R2)//R3
Nd Rth= (R1+R2)//R3
Sumit mathur said:
1 decade ago
By voltage rule vth = 120*100/(68+100+120)=41.66
rth=120+100//68=70 ohm
rth=120+100//68=70 ohm
K.Hanumantha said:
1 decade ago
Friends.
According to Thevenin theorem voltage should be short while calculating of resistor Rth, when we do that, R3 is parallel with (r1+r2). So equivalent, 168//100 = 70 ohm Rth.
Vth = r3*I. where I = Vs/(r1+r2+r3) = 100/(68+100+120) = 0.3472A.
We need Vth = I*r3 = 0.3472*120 = 41.67V.
According to Thevenin theorem voltage should be short while calculating of resistor Rth, when we do that, R3 is parallel with (r1+r2). So equivalent, 168//100 = 70 ohm Rth.
Vth = r3*I. where I = Vs/(r1+r2+r3) = 100/(68+100+120) = 0.3472A.
We need Vth = I*r3 = 0.3472*120 = 41.67V.
Christan said:
1 decade ago
Vth= VS*R3/(R1+R2+R3)
Vth= 120*100/(68+100+120)
Vth= 41.67 V
Rth= R3*(R1+R2)/(R1+R2+R3)
Rth= 120*(68+100)/(68+100+120)
Rth= 120*168/288
Rth= 20160/288
Rth= 70 Ohms
Vth= 120*100/(68+100+120)
Vth= 41.67 V
Rth= R3*(R1+R2)/(R1+R2+R3)
Rth= 120*(68+100)/(68+100+120)
Rth= 120*168/288
Rth= 20160/288
Rth= 70 Ohms
Kusuma said:
1 decade ago
The resistances 68 and 100 are in series ; 68+100=168.
168 ohms is in parallel with 120 ohms. So,
Ith = (168*120) / (168+120) = 70 ohms.
Vth = R3* (Vs/R1+R2+R3).
Vth = 41.67V.
168 ohms is in parallel with 120 ohms. So,
Ith = (168*120) / (168+120) = 70 ohms.
Vth = R3* (Vs/R1+R2+R3).
Vth = 41.67V.
Loukya said:
1 decade ago
vs=R3*V/(R1+R2+R3)
Vs=46.7
Rth=R3(R1+R2)/R1+R2+R3
Rth=70
Vs=46.7
Rth=R3(R1+R2)/R1+R2+R3
Rth=70
Shivendra soni said:
1 decade ago
Rth = (R1+R2)II(R3)
= (68+100)II(120)
= 70 ohm.
Vth = I (loop current)*R3
= [Vs/(R1+R2+R3)]*R3
= (100/288)*120
= 0.347*120
= 41.67V.
= (68+100)II(120)
= 70 ohm.
Vth = I (loop current)*R3
= [Vs/(R1+R2+R3)]*R3
= (100/288)*120
= 0.347*120
= 41.67V.
Smritimoy said:
1 decade ago
RTH = 68 + 100 = 168 ohm.
VTH = 100 v.
VTH = 100 v.
Saleem shah said:
1 decade ago
Rth = R3(R1+R2)/(R1+R2+R3).
Rth = 120(68+100)/(68+100+120).
Rth = 120*168/288.
Rth = 20160/288.
Rth = 70 ohm.
Vth = Vs*R3/(R1+R2+R3).
Vth = 100*120/68+100+120.
Vth = 12000/288.
Vth = 41.6 v.
Rth = 120(68+100)/(68+100+120).
Rth = 120*168/288.
Rth = 20160/288.
Rth = 70 ohm.
Vth = Vs*R3/(R1+R2+R3).
Vth = 100*120/68+100+120.
Vth = 12000/288.
Vth = 41.6 v.
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