Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 1)
1.
Find the Thevenin equivalent (VTH and RTH) between terminals A and B of the circuit given below.
4.16 V, 120 
41.6 V, 120
4.16 V, 70
41.67 V, 70
Discussion:
43 comments Page 1 of 5.
Ravi said:
6 years ago
By Voltage dider rule(vth) = 100 * 120/(60 + 100 + 120) = 41.66.
And rth = (100 + 68)/(100 + 68 + 120) = 70.
And rth = (100 + 68)/(100 + 68 + 120) = 70.
(13)
Muzaffar said:
9 years ago
I = 100/288 = 0.347A.
Rth = 120/(100+68) = 70.
Vth= 0.347 * 120 = 41.6 v.
Rth = 120/(100+68) = 70.
Vth= 0.347 * 120 = 41.6 v.
(12)
Nagesh said:
1 decade ago
The resistances 68 and 100 are in series ; 68 + 100 = 168.
168 ohms is in parallel with 120 ohms. So,
Rth = (168 * 120) / (168 + 120) = 70 ohms.
Vth = R3 * (Vs/R1 + R2 + R3).
Vth = 41.67V.
168 ohms is in parallel with 120 ohms. So,
Rth = (168 * 120) / (168 + 120) = 70 ohms.
Vth = R3 * (Vs/R1 + R2 + R3).
Vth = 41.67V.
(11)
Swarnab Kanrar said:
2 years ago
Vth= Vs * R3/(R1+ R2 +R3)
= 100 * 120/(68+100+120)
= 41.66 V.
Rth = R3 * (R1 +R2)/(R1+ R2 +R3),
= 120 * (68+100)/(68+100+120),
= 70 ohm.
= 100 * 120/(68+100+120)
= 41.66 V.
Rth = R3 * (R1 +R2)/(R1+ R2 +R3),
= 120 * (68+100)/(68+100+120),
= 70 ohm.
(7)
Balram jadhav said:
10 years ago
By using vtg division rule (Vth) = Vs * R3/(R1 + R2 + R3).
and Rth = R1 ll (R2 + R3).
and Rth = R1 ll (R2 + R3).
(7)
Siddhartha said:
9 years ago
What if there is no resistance between A and B terminals?
(5)
Pinvikesh said:
2 decades ago
I am not getting answer for it and I also want the simplest way to do these problems of each modle to save time please send me and also your site is useful for alot us
(2)
Prafull gadekar said:
1 decade ago
Total Resistance,
Rt=R1+R2+R3=120+68+100 = 288ohm.
I = V/R = 100/288 = 0.347A(flowing same current in all resistance).
Now, we want to find voltage across R3=120 ohm.
V = 120*0.347 = 41.67V
Now, Rth = R3//(R1+R2) = 70 ohm.
Rt=R1+R2+R3=120+68+100 = 288ohm.
I = V/R = 100/288 = 0.347A(flowing same current in all resistance).
Now, we want to find voltage across R3=120 ohm.
V = 120*0.347 = 41.67V
Now, Rth = R3//(R1+R2) = 70 ohm.
(1)
Keerthana said:
1 decade ago
1. Find Open Circuit Voltage(Vth):
Req = 68+100+120 = 288v.
Ieq = V/Req = 100/288 = .34722 A.
Voc =100-(68*.344722)-(100*.34722).
We get Vth = Voc = 41.667v.
Isc = 100/(68+100)= 0.5952A.
Rth = Vth/Isc.
Rth = 41.667/.5952 = 70 ohm.
Req = 68+100+120 = 288v.
Ieq = V/Req = 100/288 = .34722 A.
Voc =100-(68*.344722)-(100*.34722).
We get Vth = Voc = 41.667v.
Isc = 100/(68+100)= 0.5952A.
Rth = Vth/Isc.
Rth = 41.667/.5952 = 70 ohm.
(1)
Ayushi said:
1 decade ago
Actually your doubt is common one, which usually strikes the mind anirban but R3 is not the load resistance infact the load is on a b terminal, and the load is not shown at the terminals. So the answer given that is 70 is correct.
(1)
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