Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 1)
1.
Find the Thevenin equivalent (VTH and RTH) between terminals A and B of the circuit given below.
4.16 V, 120 
41.6 V, 120
4.16 V, 70
41.67 V, 70
Discussion:
42 comments Page 2 of 5.
Kusuma said:
1 decade ago
The resistances 68 and 100 are in series ; 68+100=168.
168 ohms is in parallel with 120 ohms. So,
Ith = (168*120) / (168+120) = 70 ohms.
Vth = R3* (Vs/R1+R2+R3).
Vth = 41.67V.
168 ohms is in parallel with 120 ohms. So,
Ith = (168*120) / (168+120) = 70 ohms.
Vth = R3* (Vs/R1+R2+R3).
Vth = 41.67V.
Pinvikesh said:
2 decades ago
I am not getting answer for it and I also want the simplest way to do these problems of each modle to save time please send me and also your site is useful for alot us
(2)
Akshit raulji said:
1 decade ago
First of all open 120 ohm resistance because Vth is find across it so it should be open than applied voltage divider rule.
Vth = 100*68/(68+100). So we get 40.47v.
Vth = 100*68/(68+100). So we get 40.47v.
Christan said:
1 decade ago
Vth= VS*R3/(R1+R2+R3)
Vth= 120*100/(68+100+120)
Vth= 41.67 V
Rth= R3*(R1+R2)/(R1+R2+R3)
Rth= 120*(68+100)/(68+100+120)
Rth= 120*168/288
Rth= 20160/288
Rth= 70 Ohms
Vth= 120*100/(68+100+120)
Vth= 41.67 V
Rth= R3*(R1+R2)/(R1+R2+R3)
Rth= 120*(68+100)/(68+100+120)
Rth= 120*168/288
Rth= 20160/288
Rth= 70 Ohms
Anshu said:
10 years ago
When we have to find the venin voltage b/w two terminal then, firstly we have to remove the load resistance b/w these terminal. So why all are considering r3?
Shivendra soni said:
1 decade ago
Rth = (R1+R2)II(R3)
= (68+100)II(120)
= 70 ohm.
Vth = I (loop current)*R3
= [Vs/(R1+R2+R3)]*R3
= (100/288)*120
= 0.347*120
= 41.67V.
= (68+100)II(120)
= 70 ohm.
Vth = I (loop current)*R3
= [Vs/(R1+R2+R3)]*R3
= (100/288)*120
= 0.347*120
= 41.67V.
Swarnab Kanrar said:
1 year ago
Vth= Vs * R3/(R1+ R2 +R3)
= 100 * 120/(68+100+120)
= 41.66 V.
Rth = R3 * (R1 +R2)/(R1+ R2 +R3),
= 120 * (68+100)/(68+100+120),
= 70 ohm.
= 100 * 120/(68+100+120)
= 41.66 V.
Rth = R3 * (R1 +R2)/(R1+ R2 +R3),
= 120 * (68+100)/(68+100+120),
= 70 ohm.
(5)
EEE said:
9 years ago
@ALL.
For the kind information, R3 is opened while calculating Rth. So, actual Rth is 100+68. This is what the Venin's theorem states.
For the kind information, R3 is opened while calculating Rth. So, actual Rth is 100+68. This is what the Venin's theorem states.
RAJIV SINGH said:
9 years ago
Using voltage dider rule(vth) = 100 * 120/(60 + 100 + 120) = 41.66.
And rth = (100 + 68)/(100 + 68 + 120) = 70.
And rth = (100 + 68)/(100 + 68 + 120) = 70.
(1)
Maheshwaran said:
1 decade ago
Vth = R3*(Vs/(R1+R2+R3))= 120*(100/(68+100+120)) = 41.67 V.
Rth = R3//(R1+R2) = (120*160) / (120 + 168)= 70 ohm.
Rth = R3//(R1+R2) = (120*160) / (120 + 168)= 70 ohm.
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