Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 22)
22.
Referring to circuit given, if R1 is changed to a 68 
resistor, what will be the current through it?
resistor, what will be the current through it?
Discussion:
32 comments Page 2 of 4.
Kunal said:
1 decade ago
Applying kcl in the circuit.
We will get,
I1 + 0.04 = 0.2.
We get I1 = 0.16.
We will get,
I1 + 0.04 = 0.2.
We get I1 = 0.16.
Rstar said:
9 years ago
Apply superposition theorem both sources opposite direction.
0.2 - .04 = .16
0.2 - .04 = .16
Ross said:
9 years ago
Here resistance value doesn't affect current magnitude as it will be the difference of 0.2 and 0.04 = 0.16.
RAJIV SINGH said:
9 years ago
By current division rule = 120 * 0.2/(120 + 68) = 0.12. So total current through 68ohm resistor is 0.12 + 0.04 = 0.16.
Willstone said:
9 years ago
Current does not change in the 120 ohm line. If resistance change, then only voltage drop across it changes
Ravi said:
7 years ago
When source 2 is active then both r1 and r2 are in series so same current i.e 0.04A.
When source 1 is active then only r1 is active because r2 is open circuited so r1 gets 0.2A.
Hence net current through r1 = 0.2 - 0.04 = 0.16.
When source 1 is active then only r1 is active because r2 is open circuited so r1 gets 0.2A.
Hence net current through r1 = 0.2 - 0.04 = 0.16.
Ujwal Rajbhandari said:
2 years ago
Is1 & Is2 are independent time-invariant current sources. Is1 divides into two branches.
That's why the current through 120 ohms branch is different between Is1 & Is2. The current will not change either 120ohms is changed to 68ohms since it has an independent current source.
That's why the current through 120 ohms branch is different between Is1 & Is2. The current will not change either 120ohms is changed to 68ohms since it has an independent current source.
Ayman said:
1 decade ago
Why the current of the 0.2 amperes does not divide into two equal currents at the point between 68Ohm resistors, should not it?
Pramod thorat said:
1 decade ago
By Using current source theorems 0.2-0.04 = 0.16.
Umesh said:
1 decade ago
Apply superposition theorem; Acc.to this in first case short circuit the current source IS2 hence we have current across R2 = I*R1/R1+R2 = 0.2A*120/188 = 0.12 say (I1).
Now; in second case short circuit the current source IS1 hence we have current across R2 = 0.04 say (I2) [because current flow in least resistance path]
Hence total current across R2 = I1+I2 = 0.12+0.04 = 0.16A answer.
Now; in second case short circuit the current source IS1 hence we have current across R2 = 0.04 say (I2) [because current flow in least resistance path]
Hence total current across R2 = I1+I2 = 0.12+0.04 = 0.16A answer.
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