Electrical Engineering - Circuit Theorems and Conversions - Discussion
Discussion Forum : Circuit Theorems and Conversions - General Questions (Q.No. 22)
22.
Referring to circuit given, if R1 is changed to a 68 
resistor, what will be the current through it?
resistor, what will be the current through it?
Discussion:
32 comments Page 1 of 4.
Ujwal Rajbhandari said:
2 years ago
Is1 & Is2 are independent time-invariant current sources. Is1 divides into two branches.
That's why the current through 120 ohms branch is different between Is1 & Is2. The current will not change either 120ohms is changed to 68ohms since it has an independent current source.
That's why the current through 120 ohms branch is different between Is1 & Is2. The current will not change either 120ohms is changed to 68ohms since it has an independent current source.
NIKHIL SINGH said:
6 years ago
Let current =i.
At any node sum of total current =0.
i+0.2-0.04=0.
Hence i= 1.6(leaving from node).
At any node sum of total current =0.
i+0.2-0.04=0.
Hence i= 1.6(leaving from node).
(1)
Ravi said:
7 years ago
When source 2 is active then both r1 and r2 are in series so same current i.e 0.04A.
When source 1 is active then only r1 is active because r2 is open circuited so r1 gets 0.2A.
Hence net current through r1 = 0.2 - 0.04 = 0.16.
When source 1 is active then only r1 is active because r2 is open circuited so r1 gets 0.2A.
Hence net current through r1 = 0.2 - 0.04 = 0.16.
Willstone said:
9 years ago
Current does not change in the 120 ohm line. If resistance change, then only voltage drop across it changes
RAJIV SINGH said:
9 years ago
By current division rule = 120 * 0.2/(120 + 68) = 0.12. So total current through 68ohm resistor is 0.12 + 0.04 = 0.16.
Ross said:
9 years ago
Here resistance value doesn't affect current magnitude as it will be the difference of 0.2 and 0.04 = 0.16.
Rstar said:
9 years ago
Apply superposition theorem both sources opposite direction.
0.2 - .04 = .16
0.2 - .04 = .16
Ashish said:
9 years ago
Good explanation @L.Haque.
Jagadesh said:
10 years ago
Simply the answer will be the difference of two current sources.
Why because the current from two sources enters the branch in opposite directions. So current through that branch will be I = 0.2-0.04 = 0.16 A.
What ever is the resistance placed in that branch the current through that branch will be 0.16 A.
Why because the current from two sources enters the branch in opposite directions. So current through that branch will be I = 0.2-0.04 = 0.16 A.
What ever is the resistance placed in that branch the current through that branch will be 0.16 A.
(1)
Kotresh Bullannanavar said:
10 years ago
Only IS1 is active (And IS2 current travel to the ground).
Use current divider formula I2 = Im (R1/(R1+R2)).
= 0.2*(68/ (68+68)).
= 0.1 A.
Near is 0.16 A.
Use current divider formula I2 = Im (R1/(R1+R2)).
= 0.2*(68/ (68+68)).
= 0.1 A.
Near is 0.16 A.
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