Discussion :: Circuit Theorems and Conversions - General Questions (Q.No.13)
Find the current in R2 of the given circuit, using the superposition theorem.
Answer: Option C
No answer description available for this question.
|M.V.Krishna/Palvoncha said: (Dec 19, 2011)|
|From super position theorem
case 1: using only Vs1 and shorting Vs2.
case 2: using only Vs2 and shorting Vs1.
Adding case1 I(R2)+ case2 I(R2), because both currents are flowing in same direction.
We get 33.3mA+16.7mA=50mA
|Renish said: (Feb 2, 2016)|
|In this question also apply the millman's theorem and it was very easy and fast technique.|
|Ritesh Kesharwani said: (Jun 12, 2016)|
|I1 = Vs1/R1.
= 12/120 = 0.1.
I2 = Vs2/R3 .
= 6/120 = 0.05.
I = I1 + I2 .
= 0.1 + 0.05 = 0.15.
I(R2) = I * R2/(R1 + R2 + R2).
= 0.15 * 120/360.
|Chhatrapal said: (Feb 1, 2017)|
i.e.12/120 + 120.
= 50 * 10^-3.
|Hodavid said: (Jan 29, 2019)|
|Voltage for R2 = Vs1-Vs2.
12-6 = 6v.
Try the different options V/R.
6/50mA = 120.
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