Electrical Engineering - Capacitors - Discussion
Discussion Forum : Capacitors - General Questions (Q.No. 12)
12.
A sine wave voltage is applied across a capacitor. When the frequency of the voltage is decreased, the current
Discussion:
9 comments Page 1 of 1.
Dustu said:
1 decade ago
Current i=dq/dt=d(CV sin2pift)/dt
(AC applied so v =v sin 2 pift, where pi=3.14, f=frequency, t=time)
So, as f decreases I also decreases.
(AC applied so v =v sin 2 pift, where pi=3.14, f=frequency, t=time)
So, as f decreases I also decreases.
120890 said:
1 decade ago
Xc=1/(2*PI*f*c)
if 'f' decreases ,'Xc' increases
if reactance 'Xc' decreases, current automatically get increases.
if 'f' decreases ,'Xc' increases
if reactance 'Xc' decreases, current automatically get increases.
Ravi putta said:
1 decade ago
f decrease then xc will increase. So I will be decrease.
Saurav said:
9 years ago
Give anyone relation between I and Xc.
Mangesh kotwal said:
9 years ago
I = V/Xc .
But Xc = 1/2*fC.
So f (frequency) decrease Xc increase.
Xc increase, I (current) decrease.
But Xc = 1/2*fC.
So f (frequency) decrease Xc increase.
Xc increase, I (current) decrease.
Satish chaurasiya said:
8 years ago
I agree with the given answer decrease.
Basant dev said:
8 years ago
xc = 1/2pifc if f decrease xc increase it means I decrease.
D Shwetha said:
7 years ago
@Mangesh. Your explanation is right.
R=Xc or XL then I=V/Xc.
Xc is inversely proportional to frequency(Xc=1/2πfc).
Frequency decreases means Xc increases then Xc is inversely proportional to I.
Option D is right.
R=Xc or XL then I=V/Xc.
Xc is inversely proportional to frequency(Xc=1/2πfc).
Frequency decreases means Xc increases then Xc is inversely proportional to I.
Option D is right.
(1)
Sai said:
5 years ago
Here, Xc increases mean capacitive reactance increases so the current decreases.
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