Electrical Engineering - Branch, Loop and Node Analyses - Discussion

Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 2)
2.
What is the current through R2?

3.19 A
319 mA
1.73 A
173 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
16 comments Page 1 of 2.

Harpreet said:   1 decade ago
Simply apply node base analysis and solve it by KCL Law.

Samyu said:   1 decade ago
Apply nodal analysis find voltage Va then by applying ohms law.

Ooops said:   1 decade ago
Isn't there any simple way to solve that porblem.

Rita J said:   1 decade ago
Applying kcl at node A and taking node B as refrence:

(15-va)/68-va/30-(va-8)/100=0

va=5.1689v;

Ir2=va/30=5.1689/30=0.172A=172mA;

Ashish singhal said:   1 decade ago
By appling mesh analysis

15=68i'+ 30(i'-i")
15=98i'-30i"

Now at second battery

-8=100i"+30*(i'-i")
-8=-30i'+130i"

After calculation

i'=.145
i"= -.028

So total current in 30 ohm resistance

i' - i"

0.145 - (-0.028)

= 0.173 A or

= 173 mA.

Siddhartha said:   1 decade ago
Applying kvl to the circuit,

((v-15)/68)+(v/30)+((v-8)/100).
On solving above expression we get 5.171v.

Current at R2= 5.17/30=0.172 amps.
172 milli amps.

Dinesh kumar t said:   1 decade ago
Applying kcl at node A and taking node B as refrence:

(15-va)/68-va/30-(va-8)/100=0

va=5.1689v;

Ir2=va/30=5.1689/30=0.172A=172mA.

Sunilkumar v said:   1 decade ago
Apply nodal analysis for the circuit. After getting Va value, we can find current at 30 ohm.res

(15-VA)/68 - (VA-0)/30 - (VA-8)/100 = 0.

VA = 5.169.

R2 = VA/30.

R2 = 5.169/30.

R2 = 173 mA.
(2)

Julius said:   9 years ago
Can you please elaborate the solution so that I can understand. Thanks.

Pente vinodkumar said:   9 years ago
By applying loop analysis at first loop.

15 = 68i'+ 30(i'+i").
15 = 98i'+ 30i".

Now at second loop:

8 = 100i"+30*(i'+i").
8 = 30i'+130i".

After calculation:

i' = 0.145.
i" = 0.028.

So total current in 30 ohm resistance.

i' + i".

0.145 + 0.028.

= 173 mA.
(4)


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