Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 1)
1.
Find the node voltage VA.
Discussion:
39 comments Page 4 of 4.
Dinesh sah said:
7 years ago
4.28 is the correct answer.
Yamanappa said:
6 years ago
((Vs1 - Va) /R1)+((Vs2 - Va)/R3)) = Va/R2.
(1)
Rakesh. Parida said:
5 years ago
Thanks all for explaining it.
Balu said:
5 years ago
Thanks all for giving the solution.
(1)
Adel saeed said:
5 years ago
Thanks @Abdullah.
(1)
Abyssinia said:
5 years ago
Thanks all for explaining.
(1)
Nami-Swan Jyv said:
4 years ago
KCL: Iin = Iout.
I1 + I3 = I2.
I1 - I2 + I3 = 0.
Nodal Analysis:
(Start node minus End node)/Resistor.
((V1- Va)/R1) - ((Va-0)/R2) +((V2-Va)/R3) = 0.
Shift Solve;
Va= 4.28v.
or
Va = 4.25v.
I1 + I3 = I2.
I1 - I2 + I3 = 0.
Nodal Analysis:
(Start node minus End node)/Resistor.
((V1- Va)/R1) - ((Va-0)/R2) +((V2-Va)/R3) = 0.
Shift Solve;
Va= 4.28v.
or
Va = 4.25v.
(5)
Sharathkumar said:
4 years ago
((Va-12)/49) + (Va/24) + (Va-6)/80))=0
((24Va-288 + 49Va)/1176) + (Va-6)/80))=0
1920Va-2340 + 3920Va + 1176Va-7056=0
7016Va-30096 =0,
7016Va = 30096,
Va = 30096/7016,
= 4.28.
((24Va-288 + 49Va)/1176) + (Va-6)/80))=0
1920Va-2340 + 3920Va + 1176Va-7056=0
7016Va-30096 =0,
7016Va = 30096,
Va = 30096/7016,
= 4.28.
(10)
Pewds said:
3 years ago
@All.
Here is the soltion.
Millman's Theorem.
(Σ E/R)/Σ 1/R.
Vab = (12/49 + 0/24 +6/80) / (1/49 + 1/24 + 1/80).
Vab = 4.2896 V.
Here is the soltion.
Millman's Theorem.
(Σ E/R)/Σ 1/R.
Vab = (12/49 + 0/24 +6/80) / (1/49 + 1/24 + 1/80).
Vab = 4.2896 V.
(9)
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