Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 1)
1.
Find the node voltage VA.
Discussion:
39 comments Page 1 of 4.
Sharathkumar said:
1 year ago
((Va-12)/49) + (Va/24) + (Va-6)/80))=0
((24Va-288 + 49Va)/1176) + (Va-6)/80))=0
1920Va-2340 + 3920Va + 1176Va-7056=0
7016Va-30096 =0,
7016Va = 30096,
Va = 30096/7016,
= 4.28.
((24Va-288 + 49Va)/1176) + (Va-6)/80))=0
1920Va-2340 + 3920Va + 1176Va-7056=0
7016Va-30096 =0,
7016Va = 30096,
Va = 30096/7016,
= 4.28.
(2)
Vishal P said:
4 years ago
It's simple.
According to the KCL summation of all the currents in the circuit is zero. That only is applied here.
According to the KCL summation of all the currents in the circuit is zero. That only is applied here.
Saurav said:
7 years ago
Can anyone teach me all the network theorem node analysis?
Rj naveed said:
7 years ago
Node analysis can be solved by Kirchhoff's 1st law mean sum of all current toward junction or away from junction is equal to zero.
Neeraj said:
6 years ago
At node vA we can see that Tge current i3 is leaving so the eq must be like,
i1 + i2 - i3 = 0.
(12 - vA)/49 + (6-vA)/80-VA/24 = 0,
Va = 4.2V.
i1 + i2 - i3 = 0.
(12 - vA)/49 + (6-vA)/80-VA/24 = 0,
Va = 4.2V.
Shanawaz said:
6 years ago
Here, we can apply superposition theorem to get the solution.
Vikas kumar said:
6 years ago
4.289 volt is the right answer.
Tima said:
6 years ago
What are nodes? Please explain me.
Prosper said:
6 years ago
Current flowing through the 49ohms resistor is equal to the sum of current flowing through the 24ohms and 80ohms resistor. eg. I49 = I80 + I24.
Where I49 = (12-VA)/49,
I80 =(VA-6)/80,
I24 = VA/24,
This will give an answer of 2.2945.
Where I49 = (12-VA)/49,
I80 =(VA-6)/80,
I24 = VA/24,
This will give an answer of 2.2945.
PRIYANKA said:
6 years ago
According to Kirchofs current law.
Total incoming currents= total outgoing currents.
((12-VA) /49) + ( (6-VA) /80) = (VA/24).
VA=4.25.
Total incoming currents= total outgoing currents.
((12-VA) /49) + ( (6-VA) /80) = (VA/24).
VA=4.25.
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