Electrical Engineering - Branch, Loop and Node Analyses - Discussion

Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 1)
1.
Find the node voltage VA.

6 V
12 V
4.25 V
3 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
39 comments Page 3 of 4.

Adgamdtp said:   8 years ago
You are right @Krishana.

PRIYANKA said:   8 years ago
According to Kirchofs current law.

Total incoming currents= total outgoing currents.
((12-VA) /49) + ( (6-VA) /80) = (VA/24).
VA=4.25.

Prosper said:   9 years ago
Current flowing through the 49ohms resistor is equal to the sum of current flowing through the 24ohms and 80ohms resistor. eg. I49 = I80 + I24.

Where I49 = (12-VA)/49,
I80 =(VA-6)/80,
I24 = VA/24,
This will give an answer of 2.2945.

Tima said:   9 years ago
What are nodes? Please explain me.

Naveen Pal said:   1 decade ago
STEPS FOR NODAL ANALYSIS.

STEP 1: Choose the nodes and node voltages to be obtained.

STEP 2: Choose the currents preferably leaving the node at each
branch connected to each node.

STEP 3: Apply Kirchhoff's current law at each node with proper sign
convention.

Now apply the procedure suggested by our friends.

Shanawaz said:   9 years ago
Here, we can apply superposition theorem to get the solution.

Neeraj said:   9 years ago
At node vA we can see that Tge current i3 is leaving so the eq must be like,
i1 + i2 - i3 = 0.
(12 - vA)/49 + (6-vA)/80-VA/24 = 0,
Va = 4.2V.

Rj naveed said:   10 years ago
Node analysis can be solved by Kirchhoff's 1st law mean sum of all current toward junction or away from junction is equal to zero.

Saurav said:   10 years ago
Can anyone teach me all the network theorem node analysis?

Krishna said:   1 decade ago
((va-12)/49)+(va/24)+((va-6)/80)=0
((va-12)(1920)+(va)(3920)+(va-6)(1176))/94080=0
va(7016)-30096=0
va=30096/7016
va=4.28


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