# Electrical Engineering - Branch, Loop and Node Analyses - Discussion

Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 1)

1.

Find the node voltage

*V*_{A}.Discussion:

39 comments Page 2 of 4.
Adgamdtp said:
5 years ago

You are right @Krishana.

PRIYANKA said:
6 years ago

According to Kirchofs current law.

Total incoming currents= total outgoing currents.

((12-VA) /49) + ( (6-VA) /80) = (VA/24).

VA=4.25.

Total incoming currents= total outgoing currents.

((12-VA) /49) + ( (6-VA) /80) = (VA/24).

VA=4.25.

Prosper said:
6 years ago

Current flowing through the 49ohms resistor is equal to the sum of current flowing through the 24ohms and 80ohms resistor. eg. I49 = I80 + I24.

Where I49 = (12-VA)/49,

I80 =(VA-6)/80,

I24 = VA/24,

This will give an answer of 2.2945.

Where I49 = (12-VA)/49,

I80 =(VA-6)/80,

I24 = VA/24,

This will give an answer of 2.2945.

Tima said:
6 years ago

What are nodes? Please explain me.

Vikas kumar said:
6 years ago

4.289 volt is the right answer.

Shanawaz said:
6 years ago

Here, we can apply superposition theorem to get the solution.

Neeraj said:
6 years ago

At node vA we can see that Tge current i3 is leaving so the eq must be like,

i1 + i2 - i3 = 0.

(12 - vA)/49 + (6-vA)/80-VA/24 = 0,

Va = 4.2V.

i1 + i2 - i3 = 0.

(12 - vA)/49 + (6-vA)/80-VA/24 = 0,

Va = 4.2V.

Rj naveed said:
7 years ago

Node analysis can be solved by Kirchhoff's 1st law mean sum of all current toward junction or away from junction is equal to zero.

Saurav said:
7 years ago

Can anyone teach me all the network theorem node analysis?

Abdullah U of R said:
7 years ago

Easy way to calculate node analysis:

i1+i2+i3 = 0 it is equal to:

(12-VA)/49 + -VA/24 + (6-VA)/80 = 0.

12/49 - VA/49 - VA/24 + 6/80 - VA/80 = 0.

12/49 + 6/80 = VA (1/49 + 1/24 + 1/80).

So, VA = (12/49 + 6/80)/(1/49 + 1/24 + 1/80) = 4.28 V.

i1+i2+i3 = 0 it is equal to:

(12-VA)/49 + -VA/24 + (6-VA)/80 = 0.

12/49 - VA/49 - VA/24 + 6/80 - VA/80 = 0.

12/49 + 6/80 = VA (1/49 + 1/24 + 1/80).

So, VA = (12/49 + 6/80)/(1/49 + 1/24 + 1/80) = 4.28 V.

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