Electrical Engineering - Branch, Loop and Node Analyses - Discussion
Discussion Forum : Branch, Loop and Node Analyses - General Questions (Q.No. 3)
3.
Find branch current IR2.
Discussion:
14 comments Page 1 of 2.
Subasha Chandra Behera said:
1 decade ago
How to solve?
Soham joshi said:
1 decade ago
First apply super position and than current divider rule.
Selva said:
1 decade ago
USING KIRCHOFF'S CURRENT LAW AT CENTRAL NODE,AND TAKE IT AS NODE A,AND GROUNDED POINT NODE B(Vb=0).THEN WE CAN GET,
((Va-12)/68)+((Va-0)/37)+((Va-4)/90)=0
(1665(Va-12)+3060Va+1258(Va-4))/113220=0
1665Va-19980+3060Va+1258Va-5032=0
5983Va=25012
so Va=25012/5983=4.1805 Volts
CURRENT THROUGH R2=37ohms,ie., IR2=4.1805*37=154.678amps
((Va-12)/68)+((Va-0)/37)+((Va-4)/90)=0
(1665(Va-12)+3060Va+1258(Va-4))/113220=0
1665Va-19980+3060Va+1258Va-5032=0
5983Va=25012
so Va=25012/5983=4.1805 Volts
CURRENT THROUGH R2=37ohms,ie., IR2=4.1805*37=154.678amps
BOSS said:
1 decade ago
@selva
ohms law V=IR | I=V/R
I= 4.1805/37 = 113mA
ohms law V=IR | I=V/R
I= 4.1805/37 = 113mA
Shubham said:
10 years ago
Kirchoff law -net current at a junction is 0.
Drop across 37 ohm resistor comes around 5v.
I equals v/r.
Which gives answer as option C.
Drop across 37 ohm resistor comes around 5v.
I equals v/r.
Which gives answer as option C.
YAHYA said:
9 years ago
Answer of this question is 113 mA.
And by the way @Selva! how can we find the branch current using the formula which you used (IR2=4.1805*37=154.678amps)?
And by the way @Selva! how can we find the branch current using the formula which you used (IR2=4.1805*37=154.678amps)?
Mohammad faisal said:
9 years ago
Correct answer is 113 mA. So question is wrong.
Rafiqulislam said:
8 years ago
Correct answer is:
(Va-12)/68-va/37-(va-4)/90 = 0.
=> 1665(va-12)-3060va-1258(va-4) = 0.
=> 5983va = 25012.
=> va = 4.180.
Hence,
IR2 = Va/37 = 4.180/37 = 112.97 = 113mA <=
(Va-12)/68-va/37-(va-4)/90 = 0.
=> 1665(va-12)-3060va-1258(va-4) = 0.
=> 5983va = 25012.
=> va = 4.180.
Hence,
IR2 = Va/37 = 4.180/37 = 112.97 = 113mA <=
Tamil said:
8 years ago
Correct answer is 113 mA. Thanks for giving me an idea.
Pardeep singh said:
8 years ago
How is this calculation please explain?
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