Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 15)
15.
A sawtooth wave has a period of 10 ms. Its frequency is
Discussion:
6 comments Page 1 of 1.
Pavan said:
3 years ago
T = 10x10^(-3) seconds,
F = 1/T,
F = (1/10x10^(-3)].
F = [1/10^(-2)].
F = 100hz.
F = 1/T,
F = (1/10x10^(-3)].
F = [1/10^(-2)].
F = 100hz.
Rana Usama said:
5 years ago
Period = 1/frequency.
10ms = 1/frequency.
Frequency = 1/10ms.
Frequency= 1/10*10^-3.
So,
Frequency = 10^3/10.
Frequency = 1000/10.
Frequency = 100 Hz.
10ms = 1/frequency.
Frequency = 1/10ms.
Frequency= 1/10*10^-3.
So,
Frequency = 10^3/10.
Frequency = 1000/10.
Frequency = 100 Hz.
Rovi said:
8 years ago
f = (1/10) (1/ms),
f = 0.1 (1/ms),
f = 0.1*1000 (1/s),
f = 100 HZ.
f = 0.1 (1/ms),
f = 0.1*1000 (1/s),
f = 100 HZ.
MANGESH PATIL said:
8 years ago
F = 1/T * 1000,
F = 1/10 * 1000,
F = 100HZ.
F = 1/10 * 1000,
F = 100HZ.
Pankaja nayak said:
9 years ago
Thank you for your answer @Sachi.
Sachi said:
1 decade ago
f=1/t
so for t=10 ms
f=(1/10)*1000
f=1000/10
f=100 HZ
so for t=10 ms
f=(1/10)*1000
f=1000/10
f=100 HZ
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