Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 2)
2.
The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is
Discussion:
38 comments Page 3 of 4.
Waheed ullah khattak said:
9 years ago
If we change RPS to RPM then we should have to divide by 60.
NAvya said:
1 decade ago
Where 1sec=1/60min. But how you multiplied 60 in the speed.
Mahendra said:
1 decade ago
From where did the 60 came please tell me vineeta verma.
Ch Nikhil Chakravarthy said:
1 decade ago
Since f=1/T.
Here f is frequency.
T is time in seconds.
Here f is frequency.
T is time in seconds.
Mrityunjay said:
1 decade ago
Please any one tell from where 2 is came?
Vineeta verma said:
1 decade ago
f = pn/120
f = 400*60*2/120
f = 400 HZ
f = 400*60*2/120
f = 400 HZ
Raj said:
1 decade ago
Because we have to change rps to rpm.
Surya said:
8 years ago
N= 120f/p.
F= 400*60*2/120.
F= 400.
F= 400*60*2/120.
F= 400.
Hassan said:
9 years ago
How did you guys get that 120?
Bhavesh said:
1 decade ago
Sandip your answer is correct.
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