Electrical Engineering - Alternating Current and Voltage - Discussion
Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 2)
2.
The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is
Discussion:
38 comments Page 2 of 4.
Waheed ullah khattak said:
9 years ago
If we change RPS to RPM then we should have to divide by 60.
Surya said:
8 years ago
N= 120f/p.
F= 400*60*2/120.
F= 400.
F= 400*60*2/120.
F= 400.
Sunnyleon said:
8 years ago
Thank you @Sandeep.
Kiran said:
8 years ago
rps=400*60=24000=Ns.
P=2
Ns=120f/p
120*f/Ns*p
f=Ns*p/120
f=24000*2/120
f=400.
P=2
Ns=120f/p
120*f/Ns*p
f=Ns*p/120
f=24000*2/120
f=400.
D.Jyothi said:
7 years ago
As per the definition, frequency means that the number of cycles completed by one rotation.
Asim said:
7 years ago
Good explanation @Rakshith.
Mehr said:
6 years ago
For rpm; Simply convert this to the minute, we multiply 60 with rps 400*60.
Shoon said:
6 years ago
1min = 60sec.
If 400rps then 400/60 rpm.
As from small quantities to bigger quantities we do division, from bigger quantities to small we do multiplication.
Kindly explain it.
If 400rps then 400/60 rpm.
As from small quantities to bigger quantities we do division, from bigger quantities to small we do multiplication.
Kindly explain it.
Aurangzaib said:
5 years ago
Actually, rps is rev/sec so to convert it to rpm =rev/sec/60 that's why we multiply with 60 directly.
Vinothkumar said:
1 decade ago
Thanks sandeep.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers