Electrical Engineering - Alternating Current and Voltage - Discussion

Discussion Forum : Alternating Current and Voltage - General Questions (Q.No. 2)
2.
The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is
40 Hz
100 Hz
400 Hz
indeterminable
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
38 comments Page 2 of 4.

Waheed ullah khattak said:   9 years ago
If we change RPS to RPM then we should have to divide by 60.

Surya said:   8 years ago
N= 120f/p.
F= 400*60*2/120.
F= 400.

Sunnyleon said:   8 years ago
Thank you @Sandeep.

Kiran said:   8 years ago
rps=400*60=24000=Ns.

P=2
Ns=120f/p
120*f/Ns*p
f=Ns*p/120
f=24000*2/120
f=400.

D.Jyothi said:   7 years ago
As per the definition, frequency means that the number of cycles completed by one rotation.

Asim said:   7 years ago
Good explanation @Rakshith.

Mehr said:   6 years ago
For rpm; Simply convert this to the minute, we multiply 60 with rps 400*60.

Shoon said:   6 years ago
1min = 60sec.

If 400rps then 400/60 rpm.

As from small quantities to bigger quantities we do division, from bigger quantities to small we do multiplication.

Kindly explain it.

Aurangzaib said:   5 years ago
Actually, rps is rev/sec so to convert it to rpm =rev/sec/60 that's why we multiply with 60 directly.

Vinothkumar said:   1 decade ago
Thanks sandeep.


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